All categories

3 years ago

Whitney contributes 13% of her $70,600 annual salary to her 401(k) plan.

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

$61,422

Step-by-step explanation:

apex

Licemer1 [7]3 years ago

6 0

<u>Answer: </u>

option (B) $61,422

<u>Explanation:</u>

Given the annual salary is $70,600

Percent of Contribution made from the income = 13%

Pretax Salary/Income is calculated by the formula, Salary – 13% of salary

Pretax income =

$70600 - \frac{13}{100} \times 70600$

= 70600 – 9178 = 61422

Therefore whitney’s pretax income is $ 61422

Hence, option (B) is correct

You might be interested in

12y+d=−19y+t solve for y?

sergij07 [2.7K]

Without values for the other variables, I assume you're asking for a literal equation.

12y+d=-19y+t
31y+d=t
31y=-d+t
y=(-d+t)/31

8 0

3 years ago

Read 2 more answers

What is the answer a or b to this question

galina1969 [7]

The answer would be A.

Explanation:

If they enter with one car, that’s a price of $3 for the car alone. Because there’s also a fee for each person who enters, and there is a family of 5 who enters, x is representative of the cost for each person who enters. Therefore, there would be 5 x’s and one 3 that when solved would add up to the total of $45 they spent. That would mean A is correct because the equation would be x + x + x + x + x + 3 = 45.

5 0

1 year ago

What is the answer to 7b-7-8b= -15

ozzi

Answer:

b=8

Step-by-step explanation:

7b-7-8b=-15

Combine like terms

-b-7=-15

Add 7 on both sides

-b=-15+7

-b=-8

Divide by -1

b = 8

8 0

3 years ago

Read 2 more answers

Use elimination to solve each system.

stiks02 [169]

Box of Popcorn: $3.00
Drink: $2.00

I might be wrong, but hopefully that helped! :)

5 0

3 years ago

Which exponential equation is equivalent to the logarithmic equation below? c = ln 2

Sophie [7]

$\text{A logarithmic lemma: } \\ \text{It follows that: } \log_a a = 1$
$\text{Following this property, we can see that: } a^{\log_{a} a} = a$
$\text{Furthermore, we can create more general properties: } a^{\log_a b} = b$

$c = \log_e 2 \Rightarrow e^{c} = e^{\log_e 2} \\ \text{Using our third property, we see that: } e^{c} = 2$
$\text{And finally, this works for any } \log_{a} b \left\{a > 0, b \in \mathbb{R}\right\}$

6 0

3 years ago