Answer:
26% probability that they win both contracts.
Step-by-step explanation:
These following probabilities are important to solve this question:
0.4 = 40% probability of winning the first contract.
0.65 = 65% probability of winning the second contract if the first contract is won.
What is the probability that they win both contracts?
26% probability that they win both contracts.
1. Divide the first row by -4
(1, -5/4, -3/2)
2. Multiply the first row by -2
(-2, 5/2, 3)
3. Subtract the first row from the third row and restore it.
1 (1, -5/4, -3/2)
3 (0, -15/2, 1)
4. Restore the first row to the original view
(-4, 5, 6)
5. Divide the second row by 4
(0, 1, 1)
6. Multiply the second row by -15/2
(0, -15/2, -15/2)
7. Subtract the second row from the third row and restore it
2 (0, 1, 1)
3 (0, 0, 17/2)
8. Restore the second row to the original view
(0, 4, 4)
9. Multiply the main diagonal elements
-4 x 4 x 17/2 = 136
Answer: Δ = 136
week 1
week 2
difference
the difference is 18 degrees between the means
Answer:
Transcribed image text: The diagram shows two parallel lines cut by a transversal. Given mZ1 = 77º, find m22, mZ3,m24, m25, m26, m/7, and mZ8. 1\2 3 4 5 | 6 7 8 [diagram not drawn to scale ] o o o o m_2= mZ3 = mZ4= mZ5 = mZ6 = mZ7 = mZ8 = o o o
B 100% hope this hleps and make my answer brainliest and ill help you all day