Answer:
A, C and D are continuous
Step-by-step explanation:
A is a set of any number x which 30 < x <=45
B is a set that contains only 3 and 7
C is a set of any number x which 60 <= x < 100
D is a set of any number x which -infinity < x < + infinity
E is a set that contains only even whole numbers
A continuous data set is a quantitative data set representing a scale of measurement that can consist of numbers other than whole number, like decimals and fractions.
Answer:
the new ratio milk/water is 14:6 or 7:3
Step-by-step explanation:
milk/water=5/3
milk +water=5+3=8
ratio of milk=5/8 and ratio of water=3/8
if 4 liter removed from mixture then: 20=4= 16 liter
the amount of milk in 16 liter=16*5/8=10 liter of milk
the amount of water in 16 liter=16*3/8= 6 liter
add 4 liter of milk to the mixture: 10+4=14 liter of milk and 6 liter of water
the new ratio milk/water is 14:6 or 7:3
Answer:
25 m of cable per minute
Step-by-step explanation:
The unit rate is:
125 m of cable
---------------------- = 25 m of cable per minute
5 minutes
1.)
6% of 38
1% of 38 = 3.8 ( you just move the decimal placement over by one.
1% * 6 = 6%
3.8 * 6 = 6%
3.8 * 6 = 22.8
6% =22.8
2.)
5% of 90
90/5 = 5%
90/5 = 18
18 = 5%
3.)
15/5 = 9/x
15/5 = 3
3 = 9/x
(nine divided by ? is three?....3!)
3 = 9/x(3)
3 = 9/3
3 = 3
x = 3
4.)
1/12 = .8/x
Multiply each side by ten.
1/12 * 10 = 5/6
.8/x * 10 = 8/x
5/6 = 8/x
Cross Multiply (switch the second numbers around)
5x = 6*8
Simplify
5x = 48
Divide both sides by 5 to get x by itself
5x/5 = x
48/5 = 9.6
*Whoo last problem lol*
5.)
A three liter bottle costs $2.97 what is the unit rate.
Well the unit is the object we're talking about, in this case a liter bottle.
The unit rate is how much it costs or is per unit.
Now that that's out of the way...
3L = 2.97
Like the other problems we want to get x by itself, so we'll divide by three)
3L/3 = L
2.97/3 = .99
L = .99
The Unit Rate is $0.99 per liter bottle.
Hope this helped :)
Answer:
15.7 units
Step-by-step explanation:
AB = 6, BC = 3
Therefore by Pythagoras theorem
AC = 
