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luda_lava [24]
3 years ago
15

A right cylindrical solid is cut in half to form the figure shown. If the length is 20 cm and the diameter is 8 cm, what is the

surface area?
(80π + 160) cm2
(96π + 160) cm2
320π cm2
(320π + 160) cm2
Mathematics
2 answers:
jolli1 [7]3 years ago
8 0

Answer:

(96π + 160) cm2

Step-by-step explanation:

Ne4ueva [31]3 years ago
7 0

Answer:

(96π + 160) cm2

Step-by-step explanation:

i just took the test on edg 2020

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Which pair of functions are inverses of each other?  A. f(x) = \sqrt[3]{{6x}}f(x)= 3 6x​ and g(x) = {\left( {\frac{x}{6}} \righ
Simora [160]

Answer:

the answer is B

Step-by-step explanation:

6 0
3 years ago
A consumer affairs investigator records the repair cost for 4 randomly selected washers. A sample mean of $64.26 and standard de
Mashutka [201]

Answer:

Critical value: z = 1.28

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.80}{2} = 0.10

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

So

M = 1.28*\frac{27.77}{\sqrt{4}} = 17.773

The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.

The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.

The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.

7 0
3 years ago
kinata goes for swimming lessons every 5 days while wayo goes every 6 days. if both kinata and wayo had lessons together at the
Yakvenalex [24]
Answer:
30th day
Step-by-step explanation:
5*6=30
and 6*5=30
basically we have to take Lcm of 5 and 6=30
30th day they both will be together
3 0
3 years ago
2. In 2010, the population of a town is 8500. The population decreases by 4.5% each year.
Korvikt [17]
This exponential growth/decay (in this case decay because r<1) of the form:

f=ir^t, f=final value, i=initial value, r=common ratio or "rate", t=time.

Since the population decreases by 4.5% each year the common ratio is:

r=(100-4.5)/100=0.955 so we can say

P(t)=8500(0.955^t)  

....

7000=8500(0.955^t)

14/17=(955/1000)^t  taking the natural log of both sides

ln(14/17)=t ln(955/1000)

t=ln(14/17)/ln(955/1000)

t≈4.22 years (to nearest hundredth of a year)

Since t is the years since 2010, the population will fall to 7000 in the year (2010+4.22=2014.22, more than four years will have elapsed) 2015.
5 0
3 years ago
Dan has twice as many stickers as cam does. If Dan gives cam 15 of his stickers he will have 22 more than cam. How many stickers
sleet_krkn [62]
I’m not very sure but it might be 74 because if you add 15 to 22 you get 37 and 37 x 2= 72..? sorry if i’m wrong :(
7 0
3 years ago
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