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2 years ago

What is this please

Mathematics

1 answer:

Sonja [21]2 years ago

3 0

Y = 5x + 3 is an example of the Slope Intercept Form and represents the equation of a line with a slope of 5 and and a y-intercept of 3. y = −2x + 6 represents the equation of a line with a slope of −2 and and a y-intercept of 6.

You might be interested in

Select the correct solution for the expression.<br><br> 2/5+3/8

igor_vitrenko [27]

Answer: 31/41

Explanation: You multiply the numerator and denominator across such as (2 and 8)= 16 and (3 and 5)= 15.

Once that done, you just calculate it together to get

=31/40

6 0

2 years ago

Find the solution for this inequality<br> -3x + 5 < 5

n200080 [17]

Answer:

Step-by-step explanation:

-3x+5 = 2<5

two less than 5

6 0

3 years ago

PLease help me i will give brainliest

Feliz [49]

B is correct the devotion is only 2 compared to 4.

A is wrong because variate A has higher trees then variate B
C is wrong because deviation for A is 4 compared to 2 ( opposite of B)
D is wrong because 4th one is 10 for A and 13 for B. 10 is not greater than 13

7 0

2 years ago

The length of a room is 4 feet less than twice its width. The perimeter of

AlladinOne [14]

L=2W-4

PERIMETER=2L+2W

58=2(2W-4)+2W

58=4W-8+2W

58=6W-8

6W=58+8

6W=66

W=66/6

W=11 ANS. FOR THE WIDTH.

L=2*11-4

L=22-4

L=18 ANS. FOR THE LENGTH.

PROOF:

58=2*18=2*11

58=36+22

58=58

5 0

2 years ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago