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jenyasd209 [6]
3 years ago
6

Can someone work this out ? thank you

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

Answer:

Step-by-step explanation:

(x + y)² - (x - y)² = 4xy

t = a² - b²

= (√8+2)²-(√8-2)²                    (here, x = √8 & y = 2}

=4*√8*2

=8√8

=8√2*2*2

=8*2√2

=16√2

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A. 72 degrees (i hope this helped)
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I can't figure this out. ​
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Answer:

$ 9.5

Step-by-step explanation:

total money is $20

on lunch = 1/8 × 20 = 5/2 = $2.5

on movies = 2/5 × 20 = $8

total spent = 2.5+8 =$ 10.5

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3 years ago
What is the answer to this
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To make a large batch of cinnamon rolls, the baker uses 12 cups of white flour and 10 cups of whole wheat flour. All together, he uses 176 ounces of flour. The baker uses 2 fewer cups of whole wheat flour than white flour.
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3 years ago
Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations
marusya05 [52]

Answer:

Sin \angle A =0.80

Cos \angle A=0.60

Sin \angle B =0.60

Cos \angle B=0.80

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle A =\frac{BC}{BA}

Substitute values for BC and BA

Sin \angle A =\frac{8cm}{10cm}

Sin \angle A =\frac{8}{10}

Sin \angle A =0.80

Cos \angle A=\frac{AC}{BA}

Substitute values for AC and BA

Cos \angle A=\frac{6cm}{10cm}

Cos \angle A=\frac{6}{10}

Cos \angle A=0.60

Solving (b): Sine and Cosine B

In trigonometry:

Sin \theta =\frac{Opposite}{Hypotenuse} and

Cos \theta =\frac{Adjacent}{Hypotenuse}

So:

Sin \angle B =\frac{AC}{BA}

Substitute values for AC and BA

Sin \angle B =\frac{6cm}{10cm}

Sin \angle B =\frac{6}{10}

Sin \angle B =0.60

Cos \angle B=\frac{BC}{BA}

Substitute values for BC and BA

Cos \angle B=\frac{8cm}{10cm}

Cos \angle B=\frac{8}{10}

Cos \angle B=0.80

Using a calculator:

A = 53^{\circ}

So:

Sin(53^{\circ}) =0.7986

Sin(53^{\circ}) =0.80 -- approximated

Cos(53^{\circ}) = 0.6018

Cos(53^{\circ}) = 0.60 -- approximated

B = 37^{\circ}

So:

Sin(37^{\circ}) = 0.6018

Sin(37^{\circ}) = 0.60 --- approximated

Cos(37^{\circ}) = 0.7986

Cos(37^{\circ}) = 0.80 --- approximated

8 0
3 years ago
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i need to help write the equation in vertex form for the parabola with vertex at ( 2,-1) and y - intercept 5
densk [106]

Answer: y= 5/2(x-2)^2 - 1

Step-by-step explanation:

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5=a(0-2)^2 - 5

10=a(-2)^2

10=a4

a=10/4 or 5/2

5 0
4 years ago
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