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Vsevolod [243]
3 years ago
8

GIVNING BRAINLIST

Mathematics
2 answers:
podryga [215]3 years ago
4 0

Answer:

I think it might be C

Step-by-step explanation:

tatyana61 [14]3 years ago
4 0

Answer:

I think C. please give other person brainliest though!!!!

Step-by-step explanation:

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If 3x = y - 5 and x = -4, then y = ? <br> A)-7 <br> B)3 <br> C)7 <br> D)17 <br> E)9
fredd [130]

Answer:

<h3>3×(-4) = y - 5</h3><h3>= ) -12 = y -5 </h3><h3>=) -12 +5 =y </h3><h3>=) -7 = y</h3>

<h2>y =-7</h2>

8 0
3 years ago
Read 2 more answers
HELPPP. DO TODAY SO PLEASE HELP!!!!!!!!!!
oksian1 [2.3K]

Answer:

47/6cm or 7\frac{5}{6}cm

Step-by-step explanation:

FE= 2\frac{2}{3}

FA= 5/12

AB= 2/3

CD=2

ED=1\frac{1}{4}

BC= 5/6

All=47/6 or 7\frac{5}{6}

6 0
2 years ago
. How do these two processes, finding the expected value of a discrete random variable and finding the dot product
kozerog [31]

Answer:

We can conclude that on this case we have identical processes but excersise 17 use another way to present the probability distribution and as we can see the expected value can be viewed as a dot product of two vectors with one vector containing the outcomes and the other the probabilities for each possible outcome.

Step-by-step explanation:

Assuming this previous info:

Exercise 17. Suppose that we convert the table on the previous page displaying the discrete distribution for the number of heads  occurring when two coins are flipped to two vectors.

Let vector

6 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
ℓ=gT24π2 what is g equal to
V125BC [204]

If a=48Tg\pi then g=\frac{a}{48T\pi}.

Hope this helps.

4 0
3 years ago
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