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Deffense [45]
2 years ago
10

Two angels are called complementary when their measures add to 90. Two angels are called supplementary when their measures add u

p to 180 degrees
Mathematics
2 answers:
Lilit [14]2 years ago
7 0

Answer:

uhhhh i think its c^^

Step-by-step explanation:

galina1969 [7]2 years ago
4 0

Answer:

Supplementary angles are two angles whose sum is equal to 180∘. In other words when you add the measure of one angle in the pair with the other angle in the pair, they equal 180 degrees. These two angles are supplementary because together they form a straight line.Jun 5, 2017

Step-by-step explanation:

Luna~

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Esta es la respuesta 51+52+53= 156
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Elimination equation:<br> 5x-6y= 6<br> 2x+9y= 10
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Step-by-step explanation:

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I will give 70 -0ints
kaheart [24]

Answer:

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Step-by-step explanation:

<u>(a) Mean of the data</u>

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  • <u>1.8</u>

<u></u>

<u>(b) New mean after each data point increased by 10</u>

  • 12.4 + 11.6 + 13.2 + 10.3 + 11.5 / 5
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<u>(c) New mean after each data point doubled [from (b)]</u>

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8 0
2 years ago
Read 2 more answers
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
1 year ago
Solve for x 14 -2x = \frac{3 + x}{2}
Stels [109]
I think x = 2 is the answer
6 0
3 years ago
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