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laiz [17]
3 years ago
7

A 10-year maturity, 8% coupon bond paying coupons semiannually is callable in five years at a call price of $950. The bond curre

ntly sells at a yield to maturity of 7.5% (3.8% per half-year). a. What is the yield to call annually?
Business
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

6.76% annually

Explanation:

The rate of return bondholders receives on a callable bond until the call date is called Yield to call.

Yield to Call = [ C + ( F - P ) / n ] / [ (F + P ) / 2 ]

It is assumed that face value of Bond is $1,000

C = Coupon Payment = $1,000 x 3.8% = $38

F = Face value = $1,000

P = Call price = $950

n -= number of periods to call = 5 x 2 = 10 periods

Yield to Call = [ $38 + ( $1,000 - $950 ) / 10 ] / [ ( $1,000 + $950 ) / 2 ]

Yield to Call = [ $38 - 5 ] / $975 = $33 / $975 = 0.0338 = 3.38% semiannually

YTC = 3.38% semiannually = 6.76% annually

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Nutka1998 [239]

Answer:

The delivery cycle time was 25.2 hours

Explanation:

Working notes:

Consider the following formula to solve the exercise

delivery cycle time=Wait time+Process time+Inspection time+Move time+Queue time

=(12.7+1.8+0.2+4.4+6.1)

which is equal to  = 25.2 hours.

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3 years ago
A bank with a negative repricing (or funding) gap faces refinancing risk. Group of answer choices True False
guajiro [1.7K]

Answer:

True

Explanation:

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3 0
2 years ago
Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 800 items in its invento
Nitella [24]

Answer:

99 items

Explanation:

Total number of items = 6,800

The number of items per type is:

A= 6,800*0.08\\A=544\ items\\B= 6,800*0.34\\B=2,312\ items\\C= 6,800*0.58\\C=3,944\ items

The number of items of each type counted per day is:

n_A=\frac{544}{20}\\n_A=27.2\\n_B=\frac{2312}{59}\\n_B=39.2\\n_C=\frac{3944}{121} \\n_C= 32.6\\

The total number of items counted per day is:

n = n_A+n_B+n_C=27.2+39.2+32.6\\n=99\ items\ per\ day

6 0
3 years ago
Fickel Company has two manufacturing departments—Assembly and Testing & Packaging. The predetermined overhead rates in Assem
Archy [21]

Answer:

Instructions are listed below.

Explanation:

Giving the following information:

The predetermined overhead rates:

Assembly= $22 per direct labor-hour

Testing & Packaging= $18.00 per direct labor-hour

The company’s direct labor wage rate is $24.00 per hour.

Job N-60:

Assembly:

Direct materials $390

Direct labor $228

Testing & Packaging:

Direct materials $45

Direct labor $132

1) To calculate the total manufacturing cost, first, we need to allocate overhead. To do that, we need direct labor hours for each department.

<u>Assembly:</u>

Direct labor hours= 228/24= 9.5

<u>Testing:</u>

Direct labor hour= 132/24= 5.5

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Allocated MOH= 22*9.5 + 18*5.5= $308

Total manufacturing cost= direct material + direct labor + allocated overhead

Total manufacturing cost= (390 + 45) + (228 + 132) + (308)= $1,103

2) Unitary cost= 1,103/10= $110.3

6 0
2 years ago
Zhang Industries is preparing a cash budget for June. The company has $29,500 cash at the beginning of June and anticipates $98,
PtichkaEL [24]

Answer:

Amount to be borrowed  $18,040

Explanation:

The computation of the amount that should be borrowed is given below:

Opening cash balance $29,500

Add Cash Receipts $98,000

Less Cash Disbursements -$122,540

Balance before adjustment $4,960

Desired ending cash balance $23,000

Amount to be borrowed  $18,040

7 0
3 years ago
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