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AleksAgata [21]

2 years ago

6

Describe two types of organizational documents that can help you organize a job search. What is the purpose of each document? ne

ed answer asap

1 answer:

poizon [28]2 years ago

3 0

Answer: A job search should be done using various filters in the search engines so that one can get only the specific results.

Explanation:

A JOB LEADS SOURCE LIST:

It can help us to find all the specific job lists.

The information includes contact information about the source company.

A PERSPECTIVE EMPLOYER RECORD:

It is used to gather information about hiring status, recording information, and can help in asking questions related to employment.

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White Company has two departments, Cutting and Finishing. The company uses a job-order costing system and computes a predetermin

Blababa [14]

Answer and Explanation:

The computation of the predetermined overhead rate is shown below:

For Cutting department

= Variable manufacturing overhead per machine hour + (Total fixed manufacturing overhead ÷ machine hours)

= $2 + ($264,000 ÷ 48,000)

= $2 + $5.50

= $7.50

For finishing department

= Variable manufacturing overhead per direct labour + (Total fixed manufacturing overhead ÷ direct labor hours)

= $4 + ($366,000 ÷ 30,000)

= $4 + $12.20

= $16.20

4 0

3 years ago

The degree of pretax cash flow operating leverage at Rackit Corporation is 2.7 when it sells 100,000 units of its new tennis rac

coldgirl [10]

Answer:

the fixed costs for Rackit Corporation is $161,500.

Explanation:

Cash Flow DOL = 1 + Fixed Cost / EBITDA

2.7 = 1 + Fixed Cost / 95,000

1.7 = Fixed Cost / 95,000

Fixed Cost = $161,500

Therefore, the fixed costs for Rackit Corporation is $161,500.

4 0

3 years ago

Hewitt and Patel are partners, sharing gains and losses equally. They decide to terminate their partnership. Prior to realizatio

GrogVix [38]

Answer:

$12,000

Explanation:

The amount of a gain or loss on realization is the difference between the sum of capital balances of partners and cash balance after settling all liabilities.

Total capital balances = $30,000 + $20,000 = $50,000

Total loss = Cash balance - Total capital balances = $38,000 - $50,000 = $12,000 loss.

Therefore, the amount of loss on realization is $12,000.

6 0

3 years ago

How we can improve saving culture

balu736 [363]

Answer:

answer

<h2><em><u>Here are six ways you can cultivate a savings culture:</u></em></h2>

<em><u>Here are six ways you can cultivate a savings culture:HAVE A BUDGET.</u></em>
<em><u>Here are six ways you can cultivate a savings culture:HAVE A BUDGET.CONTRIBUTE MORE TO YOUR RETIREMENT. Stop procrastinating when it comes to retirement planning. ...</u></em>

8 0

2 years ago

A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

5 0

3 years ago