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ki77a [65]
3 years ago
7

Express the polynomial x^2 -x ^4 +2x^2

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

-x^4+3x^2

Step-by-step explanation:

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Which of the following is the best approximation of the volume of a sphere with a 9 cm radius?
LenaWriter [7]
Volume = 4/3 * PI * r^3
Volume = 4/3 * 3.14159 * 9^3
Volume = <span> <span> <span> 4.18879 * 729
</span></span></span>Volume = <span> <span> <span> 3,053.62 cubic centimeters

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5 0
3 years ago
I need to find the slope and b <br> Y=mx+b <br> HELP ME
Naddika [18.5K]

Answer:

y=-\frac{4}{3}x+20

Step-by-step explanation:

stupid enough

y=mx+b

\frac{y1-y2}{x1-x2}

slope = 16-12/3-6

-4/3

y=-\frac{4}{3}x+b

plug in x and y

16=-4/3(3)+b

b=20

<h2><em><u>Red</u></em></h2>
7 0
3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
3 years ago
Answer this questions right and i will give you Brainliest, Thanks, and 5 stars and thanks on profile.
katen-ka-za [31]

Answer:

1. k=5

2. a= -7

3. n=4

4. n=1

5.x=0

6. r= -4

7. b=31

8.n= -3

3 0
3 years ago
What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^
Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1

2(w2 − 2w) = 5 Expand (undo the brackets),

and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

sorry it took so long

7 0
3 years ago
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