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Vikki [24]
3 years ago
7

Will mark brainliest, please help ASAP!

Chemistry
1 answer:
Anon25 [30]3 years ago
7 0

V²+ = (B)

X³+ = (D)

Y³- = (C)

Z²- = (A)

When an element loses electrons, the element gains a positive charge

When an element gains electrons, the element gains a negative charge

NOTE: Electrons are negative charges

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How many molecules are in 68.0 g of H2S
Kryger [21]

The correct answer is 12.044 × 10²³ molecules.  

The molecular mass of H₂S is 34 gram per mole.  

Number of moles is determined by using the formula,  

Number of moles = mass/molecular mass

Given mass is 68 grams, so no of moles will be,  

68/34 = 2 moles

1 mole comprises 6.022 × 10²³ molecules, therefore, 2 moles will comprise = 6.022 × 10²³ × 2

= 12.044 × 10²³ molecules.  


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3 years ago
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Elenna [48]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
Which of the following is a correct formula unit? PbCl AlP Li3Al ClO
zavuch27 [327]

Answer:  AIP  

There are two types of substances mixture and pure substance. Mixture has NO chemical formula and a pure substance has a chemical formula. There are two types of pure substances, elements (mono atomic and molecular) and compounds ( covalent and ionic).  

Ionic compounds do not exist in independent molecular form. They form three dimensional crystal lattice, in which each ion is surrounded by oppositely charged ion.  so the ratio of ion is called the formula unit  


3 0
3 years ago
Read 2 more answers
How many particles would be found in a 1.224 g sample of K2O
lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0
3 years ago
Read 2 more answers
Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc
jeka94

Answer:

T_f = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

T_i = 21.5°C

C_{calorimeter} = 6.15 kJ/°C

T_f = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate ×  \frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

=  0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter =  C_{calorimeter} (T_f-T_i} )

21.84 kJ =6.15 kJ/°C * (T_f-21,5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)

21.84 KJ = (6.15 kJ/^0C * T_f) - 132.225 kJ

21.84 KJ + 132.225 kJ = (6.15 kJ/^0C * T_f)

154.065 kJ = (6.15 kJ/^0C * T_f)

T_f = \frac{154.065kJ}{6.15kJ/^0C}

T_f =25.05°C

4 0
3 years ago
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