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2 years ago

Which characteristics define a liquid?

Chemistry

2 answers:

Nadya [2.5K]2 years ago

8 0

Hello I am absolutely positve the answer is D. Mark brainliest :)

ELEN [110]2 years ago

4 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Liquid state is the second state of matter. In this state, the particles are present in random and irregular pattern. The particles are closely arranged but they can move from one place to another. The intermolecular forces between the particles are less as compared to the solid state.

The liquids have a definite volume but does not have a fixed shape as they can take up the shape of container in which they are kept.

The particles have spaces in between them, thus they have high molecular motion.

Hence, the correct answer is Option D.

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The rate constant for a certain reaction is measured at two different temperatures:

Talja [164]

Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]$

$k_1$ = rate constant at temperature $T_1$ = $2.3\times 10^8$

$k_2$ = rate constant at temperature $T_2$ = $4.8\times 10^8$

$E_a$ = activation energy = ?

R= gas constant = 8.314 J/kmol

$T_1$ = temperature = $280.0^0C=(273+280)=553K$

$T_2$ = temperature = $376.0^0C=(273+376)=649K$

Putting in the values ::

$ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]$

$E_a=22689.8J/mol$

The activation energy Ea for this reaction is 22689.8 J/mol

3 0

2 years ago

Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati

Korvikt [17]

Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

$\Delta S=\frac{\Delta H_{vap}}{T_b}$

where,

$\Delta S$ = change in entropy

$\Delta H_{vap}$ = change in enthalpy of vaporization = 40.5 kJ/mol

$T_b$ = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

$\Delta S=\frac{\Delta H_{vap}}{T_b}$

$\Delta S=\frac{40.5kJ/mol}{352K}$

$\Delta S=115J/mol.K$

Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K

8 0

2 years ago

What is the independent variable in this reaction

jolli1 [7]

Answer:

Explanation:

what wheres the answer???

6 0

2 years ago

An area in the desert where water is found is known as an.

lbvjy [14]

Answer:

Oasis

Explanation:

An area in the desert that has water in it is called an oasis.

6 0

1 year ago

7. How many moles are in 18.00 x 1023 particles of AICIZ?

Andrej [43]

Answer:

<h3>The answer is option A</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{18.0 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{18}{6.02} \\ = 2.99003322...$

We have the final answer as

<h3>2.99 moles</h3>

Hope this helps you

7 0

2 years ago