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fgiga [73]
3 years ago
9

How many major Foods or food groups accounts for 90% of food allergens?​

Chemistry
1 answer:
kow [346]3 years ago
6 0

Answer:

Eight foods are responsible for 90 percent of all reactions: peanut, tree nut, milk, egg, fish, shellfish, soy, and wheat.

hope it helped

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Please help asap and thank you
natulia [17]

Answer:

Metamorphic rock

Explanation:

metamorphic rocks do not get hot enough to melt they just get denser if they did they would become igneous rocks.

7 0
3 years ago
Albino trees exist in nature, but they’re rare. These trees contain a gene mutation that causes them to lack chlorophyll, so the
77julia77 [94]

Answer:

They need to use energy from other tress to survive so that they can do basic functions, like absorbing nutrients from the ground, and growing back leaves. They don't have chlorophyll, so they need that energy to do the functions I mentioned above.

Explanation: Hope this helps!

5 0
3 years ago
Read 2 more answers
A 104 m3 thoroughly mixed pond has a water inflow and outflow of 5 m3/h. The inflow water contains 0.01 mol/m3 of chemical. Chem
Naily [24]

Answer:

C ≈ 1.44 × 10⁻³ mol/m³

Explanation:

The given information are;

The liquid volume the pond can hold = 104 m³

The volume of inflow into the pond = 5 m³/h

The volume of outflow into the pond = 5 m³/h

The concentration of the chemical in the inflow water = 0.01 mol/m³

The concentration of the chemical discharged directly into the water = 0.1 mol/h

The concentration, c_{(inflow)}, of chemical that enters the water through inflow per hour is given as follows;

c_{(inflow)} = 0.01 mol/m³ × 5 m³/h = 0.05 mol/h

The concentration, c_{(discharge)}, of chemical that enters the water through direct discharge per hour is given as follows;

c_{(discharge)} = 0.1 mol/h

The total concentration that enters the pond per hour is given as follows;

c_{(inflow)} + c_{(discharge)} = 0.1 mol/h + 0.05 mol/h = 0.15 mol/h

Whereby the water in the pond properly mixes with the pond, we have;

The concentration of chemicals (C) in the outflow water = 0.15 mol/(104 m³) ≈ 0.00144 mol/m³

C ≈ 1.44 × 10⁻³ mol/m³.

4 0
3 years ago
Вычислить равновесные концентрации частиц в растворе, содержащем 0,01 моль/л Cu(NO3)2 и 1,0 моль/л NH3.
Wewaii [24]

Answer:

i dOnT SpEaK uR lAnGuAgE

Explanation:

ReEEEeEeEeEeEeEeEeEeeEEEeeeeEEEEeeeeeEEeEEeeeeeEEEEEeeeEee

3 0
3 years ago
What is the pH of 0.000134 M solution of HCI?
mafiozo [28]

Answer: The pH will be 3.87

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,

1 mole of HCl gives 1 mole of H^+

Thus 0.000134 moles of HCl gives =\frac{1}{1}\times 0.000134=0.0001342 moles of H^+

Putting in the values:

pH=-\log[0.000134]

pH=3.87

Thus the pH will be 3.87

5 0
3 years ago
Read 2 more answers
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