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ZanzabumX [31]
3 years ago
15

I don't know the answer to this question and I need help to figure it out. Thank you for helping!

Chemistry
1 answer:
AlekseyPX3 years ago
7 0

Answer:

P₄O₆ + 2O₂ ⟶ P₄O₁₀

Step-by-step explanation:

We have two equations:  

(I)  P₄ + 3O₂ → P₄O₆  

(II) P₄ + 5O₂ → P₄O₁₀

From these, we must devise the target equation:  

(III) P₄O₆ + __O₂ ⟶ P₄O₁₀

The target equation has P₄O₆ on the left, so you reverse Equation (I).  

(IV) P₄O₆ ⟶ P₄ + 3O₂

The target equation has P₄O₁₀ on the right, so we rewrite Equation (II).  

(II) P₄ + 5O₂ → P₄O₁₀

Now, you add Equations (IV) and (II), <em>cancelling species</em> that appear on opposite sides of the reaction arrows.

We get the target Equation (III):  

(IV)           P₄O₆ ⟶ <u>P₄</u> + <u>3O₂</u>

(II)   <u>P₄</u> +  <u>5</u>2O₂ ⟶ P₄O₁₀

(III)  P₄O₆ + 2O₂ ⟶ P₄O₁₀

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muminat

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

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