Question

on dividing $200 between A and B such that twice of A's share is less than 3 times than B's share by $20

Answer 1

Answer:

Share of A is $116 and Share of B is $84.

Step-by-step explanation:

Let the share of A be $x$

Let the share of B be $y$

Given:

$200 is shared between A and B

So, $x+y =\ 200\ \ \ \ equation \ 1$

Also given;

twice of A's share is less than 3 times than B's share by $20

$2x= 3y -20\\2x-3y = -20 \ \ \ \ equation \ 2$

Solution:

Now multiplying equation 1 by 3 we get,

$3x+3y=600 \ \ \ \ equation \ 3$

Now Adding equation 2 and equation 3 we get

$(2x-3y = -20)+ (3x+3y=600)\\5x=580\\\\x=\frac{580}{5}=\ 116$

Now Substituting the value of x in equation 1 we get,

$x+y=200\\116+y=200\\y=200-116 = \ 84$

Hence, Share of A is $116 and Share of B is $84.