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icang [17]
3 years ago
6

(x - 2)² + 6x – 7 Which of the following is equivalent to

Mathematics
1 answer:
podryga [215]3 years ago
6 0

Answer:

x^2 +2x-3

Step-by-step explanation:

Given

(x - 2)\² + 6x - 7

Required

The equivalent

We have:

(x - 2)\² + 6x - 7

Expand

(x - 2)\² + 6x - 7 = x^2 -2x-2x +4 +6x - 7

Collect like terms

(x - 2)\² + 6x - 7 = x^2 -2x-2x+6x +4  - 7

(x - 2)\² + 6x - 7 = x^2 +2x-3

Hence, the equivalent is:

x^2 +2x-3

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Find the slope of the line described by the equation. 4y = 152 − 19x
Softa [21]

Answer: - 19/4

Step-by-step explanation:

To find the slope , all we need to do is to write the equation in the form y = mx + c , where m is the slope and c is the y - intercept.

That means we need to make y the subject of the formula in the equation.

4y = 152 - 19x

Divide through by 4

y = 152/4 - 19x/4

y = 38 - 19x/4

Therefore the slope is -19/4

4 0
3 years ago
Read 2 more answers
Select the correct answer.What is 2/5 divided by 4/7 by equal to?A.7/5 B.7/10 C.10/7 D.7/5
qwelly [4]
The answer would be A . 7/5
7 0
3 years ago
Read 2 more answers
Sonic rolls up a slope at 9.4 m/s. after 3.0 he is rolling back down ay 7.4 m/s. how far up the hill is he at this time?
vovikov84 [41]
U= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.


6 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
Helppppppppppppppppppppppppppppppppppppppppppppppppppppp
DiKsa [7]

Answer:

8.40049 × 10^7

Step-by-step explanation:

4 0
4 years ago
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