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azamat
3 years ago
5

Evaluate 8 7/8+(7 5/6-2 1/3)

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

14 \frac{3}{8}

Step-by-step explanation:

I assume you mean this:

8 \frac{7}{8} +(7 \frac{5}{6} -2\frac{1}{3} )

Lets begin with the parentheses. When operating with fractions, we need them to have the same denominator. Looking at the expression in the parenthesis, we can see that the denominator of 5/6, that being 6, is twice that of 1/3, that being 3. Thus, if we multiply the numerator and denominator of 1/3 by 2, the result will be a fraction of same value, but with denominator 6, which we can work with.

\frac{1*2}{3*2}

\frac{2}{6}

Now we can replace this in the original parenthesis

(7 \frac{5}{6} -2\frac{2}{6})

We can now evaluate the parenthesis. 7-2=5, which leaves us with 5 5/6 - 2/6. Since the two fractions have the same denominator, we can subtract the numerator of 2/6 from 5/6. This gives us with 3/6, which we add to the 5 from before.

5\frac{3}{6}

The numerator and denominator of 3/6 are both divisible by three, so we can simply the fraction.

5\frac{1}{2}

Now that we have solved the parenthesis, we can plug our solution back into the original expression.

8 \frac{7}{8} +5\frac{1}{2}

We now have a similar problem to the parenthesis, where our fractions have different denominators. However, you may notice that the denominator of 7/8 (8) is four times larger than the denominator of 1/2 (2). Thus, if we multiply the numerator and denominator of 1/2 by four, we will have a new fraction of equal value, but with denominator 8.

\frac{1*4}{2*4}

\frac{4}{8}

Now lets update our expression with this information.

8 \frac{7}{8} +5 \frac{4}{8}

8+5=1313\frac{7}{8} +\frac{4}{8}, so we can further simplify the expression.

Since the denominators of the fractions are the same, we can combine the numerators. 7+4=11

13 \frac{11}{8}

We can simplify the fraction by taking one whole out of it (8/8) and adding it as 1 instead. 11-8=3, thus the fraction that remains is 3/8.

14 \frac{3}{8}

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The difference between two positive integers is 7 and the sum of their squares is 949. What are the numbers?
Darina [25.2K]

Answer:

25 and 18

Step-by-step explanation:

Let's say that the first number is x and the second one is y.

First, the difference between them is 7, so x-y=7

Next, the sum of their squares is 949, so x²+y² = 949

We have

x-y=7

x²+y²=949

One thing we can do to solve this problem is to solve for x in the first equation, plug that into the second equation, and go from there

Adding y to both sides in the first equation, we have

x = 7 + y

Plugging that into the second equation for x, we have

(7+y)²+ y² = 949

expand

(7+y)(7+y) + y² = 949

49 + y² + 7y + 7y + y² = 949

combine like terms

2y² +14y + 49 = 949

subtract 949 from both sides to put this in the form of a quadratic equation

2y² + 14y - 900 = 0

divide both sides by 2

y² + 7y - 450 = 0

To factor this, we want to find 2 numbers that add up to 7 and multiply to -450.

The factors of 450 are as follows:

1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 30, 45, 50, 75, 90, 150, 225, and 450.

Note that we want to find two numbers with a difference of 7, as one will have to be negative for the multiplication to end up at -450. Two numbers that stand out are 18 and 25. To make them add up to 7, 18 can be negative. We therefore have

y² + 25y - 18y - 450 = 0

y(y+25) - 18(y+25) = 0

(y-18)(y+25) = 0

Solving for 0,

y-18 = 0

add 18 to both sides

y=18

y+25 = 0

subtract 25 from both sides

y= -25

As the question states "two positive integers", this means that y must be positive, so y = 18. We know x-y=7, so

x-18 = 7

add 18 to both sides to isolate x

x = 25

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Step-by-step explanation:

Rewriting as exponents

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We know that a^ b^c = a^(b*c)

x^ (5/3) y ^ 1/3

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