Answer:
It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)
Step-by-step explanation:

Answer:
The diameter cannot solve for the circumference, you need the Radius to do it.
Step-by-step explanation:
If you want to use the Diameter divide the Diameter by 2. Diameter=D Radius=R
So to find the circumference of a Circle, 2÷D=R. Now we do 2
R. So now to find the answer we have to do 2x
xR
1. Consider right triangle ABK. The hypotenuse AB is 6 un. and the leg AK is 3 un. Since the leg is half of the hypotenuse, then the opposite to the leg angle is 30°. This means that m∠ABK=30°. Then m∠BAK=90°-30°=60°.
2. By the Pythagorean theorem,

3. Consider right triangle ABD. In this triangle AD is hypotenuse and m∠ADB=90°-m∠BAD=90°-60°=30°. Then the leg AB opposite to the angle 30° is half of the hypotenuse and AD=12 un.
4. The area of parallelogram is

Answer:
![(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B9%7D%29%28%5Csqrt%7B9%7D%29%5Cdiv%20%5Csqrt%5B4%5D%7B9%5E5%7D%3D%5Cfrac%7B%5Ctextbf%7B1%7D%7D%7B%5Csqrt%7B%5Ctextbf%7B9%7D%7D%7D)
Step-by-step explanation:
Given expression is
![(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B9%7D%29%28%5Csqrt%7B9%7D%29%5Cdiv%20%5Csqrt%5B4%5D%7B9%5E5%7D)
The above expression can be written as

(by using the formula
)
(by using the formulae
and
)



![(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B9%7D%29%28%5Csqrt%7B9%7D%29%5Cdiv%20%5Csqrt%5B4%5D%7B9%5E5%7D%3D%5Cfrac%7B%5Ctextbf%7B1%7D%7D%7B%5Csqrt%7B%5Ctextbf%7B9%7D%7D%7D)
Answer:
20
Step-by-step explanation:
4^2 = 16
-2^2 =-4
16 -(-4) =20