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Tom [10]
3 years ago
8

How to do this question plz answer me step by step plzz plz ​

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

£13496.80

Step-by-step explanation:

We can ignore the £ sign for now, that is just units.

If we decrease a number by 4.5%, we will have to find 100-4.5=95.5% of 14132.77.

We can easily do this by setting up a proportion.

\frac{x}{14132.77} = \frac{95.5}{100}

Multiply 14132.77 by 95.5:

14132.77\cdot95.5=1349679.535

Divide by 100:

1349679.535\div100=13496.79535

Rounding this to two decimal places, it simplifies to 13496.80.

Hope this helped!

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Prove algebraically that n^2-2-(n-2)^2 is always even
Juliette [100K]

Answer:

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Step-by-step explanation:

{n}^{2}  - 2 - ( {n}^{2}  + 4 - 4n) =  \\  {n}^{2}  - 2 - {n}^{2}   - 4  +  4n = \\ 4n - 6 = 2(2n - 3)

6 0
2 years ago
Read 2 more answers
Explain what the diameter of a circle is. If you had the diameter of a circle, how could you solve for the circumference?
Anna11 [10]

Answer:

The diameter cannot solve for the circumference, you need the Radius to do it.

Step-by-step explanation:

If you want to use the Diameter divide the Diameter by 2. Diameter=D Radius=R

So to find the circumference of a Circle, 2÷D=R. Now we do 2\piR. So now to find the answer we have to do 2x\pixR

3 0
3 years ago
Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, AABCD
jenyasd209 [6]

1. Consider right triangle ABK. The hypotenuse AB is 6 un. and the leg AK is 3 un. Since the leg is half of the hypotenuse, then the opposite to the leg angle is 30°. This means that m∠ABK=30°. Then m∠BAK=90°-30°=60°.

2. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9,\\\\BK^2=27,\\\\BK=3\sqrt{3}\ un.

3. Consider right triangle ABD. In this triangle AD is hypotenuse and m∠ADB=90°-m∠BAD=90°-60°=30°. Then the leg AB opposite to the angle 30° is half of the hypotenuse and AD=12 un.

4. The area of parallelogram is

A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.

5 0
3 years ago
Please solve ASAP!<br> (⁴√9)(√9) ÷ ⁴√9⁵
-Dominant- [34]

Answer:

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}

Step-by-step explanation:

Given expression is

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}

The above expression can be written as

\frac{(9)^{\tfrac{1}{4}}(9^{\tfrac{1}{2}})}{(9^5)^{\tfrac{1}{4}}}

=\frac{9^{\tfrac{1+2}{4}}}{9^{\tfrac{5}{4}}}    (by using the formula a^m\times a^n=a^{m+n})

=9^{\tfrac{3}{4}}\times 9^{\tfrac{-5}{4}}   (by using the formulae {(a^m)}^n=a^{mn} and \frac{a^m}{a^n}=a^{m-n})

=9^{\tfrac{-2}{4}}

=9^{\tfrac{-1}{2}}

=\frac{1}{9^{\tfrac{1}{2}}}

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}

4 0
3 years ago
Evulate a^2 - b^2 if a=4 and b= -2
Helen [10]

Answer:

20

Step-by-step explanation:

4^2 = 16

-2^2 =-4

16 -(-4) =20

8 0
3 years ago
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