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Zarrin [17]
2 years ago
11

Solve the following equation for x: 6x-16=14

Mathematics
1 answer:
Ivenika [448]2 years ago
8 0

To solve the equation for x, first, we add 16 from both sides of the equation:

\begin{gathered} 6x-16+16=14+16, \\ 6x=30. \end{gathered}

Now, we divide by 6:

\frac{6x}{6}=\frac{30}{6}.

Finally, we get that:

x=5.

Answer:

x=5.

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svet-max [94.6K]
A. 16x11 = 176 + 30x8.75 = 262.5. 176+262.5 = 438.5. Not 470
B. 20x11 = 220 + 26x8.75 = 227.5. 220+227.5 = 448. Not 470
C. 30x11 = 330 + 16x8.75 = 140. 330+140 = 470. C. is the correct answer
D. 31x11 = 341 + 15x8.75 = 131.25. 341+131.25 = 472.25 Not 470
6 0
3 years ago
-3D - 15 i dont get how to do gcm or factoring out
Nookie1986 [14]

Answer:

-3 (D+5)

Step-by-step explanation:

Problem: -3D -15

what you do is find the highest number each one is divisible by.

In this case they can both be divided by -3.

Bring it out of the parenthesis and leave the rest inside

Thus leaving -3 (D+5)

5 0
4 years ago
Help I don’t understand
OverLord2011 [107]
Rotation about a point does not change any dimensions. C'D' = CD = 2.8 units.
8 0
4 years ago
Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
The system of equations has no solution:<br> True or False?<br> y = (2/3)x - 5<br><br> 4x - 6y = 30
Anni [7]
It’s false because, a system of linear equations has one solution when the graphs intersect at a point.
8 0
4 years ago
Read 2 more answers
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