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yanalaym [24]
3 years ago
13

In what step of the Design Process would you interview a professional engineer?

Engineering
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

when you are in the design process so you can get his insite

Explanation:

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A disk of radius 2.1 cm has a surface charge density of 5.6 µC/m2 on its upper face. What is the magnitude of the electric field
Assoli18 [71]

Answer:

=6.3*10^3 N/C

Explanation:

solution:

from this below equation (1)

E=σ/2εo(1-\frac{z}{\sqrt{z^2-R^2} } )...........(1)

we obtain:

=5.6*10^-6 \frac{c}{m^2} /2(8.85*10^-12\frac{c^2}{N.m^2} ).(1-\frac{9.5 cm}{\sqrt{9.5^2-2.1^2} } )

=6.3*10^3 N/C

8 0
3 years ago
When compared to early vehicles, modern vehicles do not have?
KIM [24]
Modern vehicles do not have steam or coal engines
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3 years ago
Read 2 more answers
The Gill Art Gallery wishes to maintain data on their customers, artists and paintings. They may have several paintings by each
sashaice [31]

Answer:

a. $79,122.50

b. 314. 84 miles.

c. 700 ways.

Explanation:

a. Compound interest = A = P (1 + r/n)nt ;

where P = 7500 (principal amount)

r = 15% (interest rate)

t = 16 (no of years)

n = 4 (no of times compounded annually.)

and finally A is the Amount (present value after 16 years)

Upon calculation A = $79,122.50.

b. Answer: 314. 84 miles.

Explanation:

Given data. 160 miles / 7.75 liters of gasoline

Therefore 1 liter of gasoline = 160/7.75 = 20.645 miles/ liter.

15.25 liters of gasoline = 20.645 * 15.25 = 314.84 miles.

c. Answer: 700 ways.

Explanation:

This is an application of generalized principle of counting.

4 Americans can be choosen from 7 Americans = 7C4 = 35

3 Russians can be choosen from 6 Russians = 6C3 = 20.

Total number of ways = (7C4)* (6C3) = 35 * 20 = 700 ways.

3 0
3 years ago
What types of issues MAY occur to slow or prevent the best outcome?
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Answer:

im sorry but i cant find any studies about this and im 3 days late

4 0
3 years ago
Determine the real roots of f (x) = −0.6x2 + 2.4x + 5.5:(a) Graphically.(b) Using the quadratic formula.(c) Using three iteratio
zubka84 [21]

The three methods used to find the real roots of the function are,

graphically, the quadratic formula, and by iteration.

The correct vales are;

(a) Graphically, the roots obtained are; <u>x ≈ -1.629, and 5.629</u>

(b) Using the quadratic formula, the real roots of the given function are; <u>x ≈ -1.62589, x ≈ 5.62859</u>

(c) Using three iterations, we have; the bracket is x_l = <u>5.625</u>, and x_u =<u> 6.25</u>

Reasons:

The given function is presented as follows;

f(x) = -0.6·x² + 2.4·x + 5.5

(a) The graph of the function is plotted on MS Excel, with increments in the

x-values of 0.01, to obtain the approximation of the x-intercepts which are

the real roots as follows;

\begin{array}{|c|cc|}x&&f(x)\\-1.63&&-0.00614\\-1.62&&0.03736\\5.62&&0.03736 \\5.63&&-0.00614\end{array}\right]

Checking for the approximation of x-value of the intercept, we have;

x = -1.63 + \dfrac{0 - (-0.00614)}{0.0376 - (-0.00614)} \times (-1.62-(-1.63)) \approx -1.629

Therefore, based on the similarity of the values at the intercepts, the x-

values (real roots of the function) at the x-intercepts (y = 0) are;

<u>x ≈ -1.629, and 5.629</u>

(b) The real roots of the quadratic equation are found using the quadratic

formula as follows;

The quadratic formula for finding the roots of the quadratic equation

presented in the form f(x) = a·x² + b·x + c, is given as follows;

x = \mathbf{ \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}}

Comparison to the given function, f(x) = -0.6·x² + 2.4·x + 5.5, gives;

a = -0.6, b = 2.4, and c = 5.5

Therefore, we get;

x = \dfrac{-2.4\pm \sqrt{2.4^{2}-4\times (-0.6)\times 5.5}}{2\times (-0.6)} = \dfrac{-2.4\pm\sqrt{18.96} }{-1.2} = \dfrac{12 \pm\sqrt{474} }{6}

Which gives

The real roots are; <u>x ≈ -1.62859, and x ≈ 5.62859</u>

(c) The initial guesses are;

x_l = 5, and x_u = 10

The first iteration is therefore;

x_r = \dfrac{5 + 10}{2} = 7.5

Estimated \ error , \ \epsilon _a = \left|\dfrac{10- 5}{10 + 5} \right | \times 100\% = 33.33\%

True \ error, \ \epsilon _t = \left|\dfrac{5.62859 - 7.5}{5.62859} \right | \times 100\% = 33.25\%

f(5) × f(7.5) = 2.5 × (-10.25) = -25.625

The bracket is therefore; x_l = <u>5</u>, and x_u = <u>7.5</u>

Second iteration:

x_r = \dfrac{5 + 7.5}{2} = 6.25

Estimated \ error , \ \epsilon _a = \left|\dfrac{7.5- 5}{7.5+ 5} \right | \times 100\% = 20\%

True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 6.25}{5.62859} \right | \times 100\%} \approx 11.04\%

f(5) × f(6.25) = 2.5 × (-2.9375) = -7.34375

The bracket is therefore; x_l = <u>5</u>, and x_u = <u>6.25</u>

Third iteration

x_r = \dfrac{5 + 6.25}{2} = 5.625

Estimated \ error , \ \epsilon _a = \left|\dfrac{5.625- 5}{5.625+ 5} \right | \times 100\% = 5.88\%

True \ error, \ \epsilon _t = \mathbf{\left|\dfrac{5.62859 - 5.625}{5.62859} \right | \times 100\%} \approx 6.378 \times 10^{-2}\%

f(5) × f(5.625) = 2.5 × (0.015625) = 0.015625

Therefore, the bracket is x_l = 5.625, and x_u = 6.25

Learn more here:

brainly.com/question/14950153

6 0
3 years ago
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