Answer:
Yes, the triangles are congruent by ASA
Step-by-step explanation:
we know that
If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)
In this problem
LK=MJ
∠KLJ=∠KMJ
∠LKJ=∠MJK
so
Two angles and the included side is equal in triangle JKL and triangle KJM
therefore
JKL≅KJM ----> by ASA
Answer:
0 + (-2.5) + 5
Step-by-step explanation:
from 0 to -2.5 then to 5 so add 0 + (-2.5) + 5
Answer:
tq eddy porada for eddy ame
Answer:
1 false
2 true
3 true
4 false
5 true
Step-by-step explanation:
f(a) = (2a - 7 + a^2) and g(a) = (5 – a).
1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial
When added together, they will be a second degree polynomial
2. true When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction
3. true f(a) + g(a) = (2a - 7 + a^2) + (5 – a)
Combining like terms = a^2 +a -2
4. false f(a) - g(a) = (2a - 7 + a^2) - (5 – a)
Distributing the minus sign (2a - 7 + a^2) - 5 + a
Combining like terms a^2 +3a -12
5. true f(a)* g(a) = (2a - 7 + a^2) (5 – a).
Distribute
(2a - 7 + a^2) (5) – (2a - 7 + a^2) (a)
10a -35a +5a^2 -2a^2 -7a +a^3
Combining like term
-a^3 + 3 a^2 + 17 a - 35
