The table below describes the smoking habits of a group of asthma sufferers. If one of the 1156 people is randomly selected, fin
d the probability that the person is a
man or a heavy smoker. Round to three decimal places as needed
71
Occasional Regular Heavy
Smoker Smoker Smoker Total
50
601
39 555
9815788 1156
Men
Women
Total
49
Nonsmoker
431
382
813
86
man or a heavy smoker. Round to three decimal places as needed
71
Occasional Regular Heavy
Smoker Smoker Smoker Total
50
601
39 555
9815788 1156
Men
Women
Total
49
Nonsmoker
431
382
813
86
1 answer:
Answer:
0.554
Step-by-step explanation:
In the figure attached, the table is shown
Total people: 1156
Nonsmoker men + occasional smoker men + regular smoker men + heavy smoker men + heavy smoker women = men + heavy smoker women = 601 + 39 = 640
Probability that the person is a man or a heavy smoker = 640/1156 = 0.554
(Notice that if you directly add heavy smoker and total men you will count twice heavy smoker men)
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Answer:
2.083 < µ1 - µ2 < 5.917
Step-by-step explanation:
We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.
The calculations of the sample means and standard deviations are done for us.
Sample 1: Catalyst 1
n = 12, x = 85, s = 4
Sample 2: Catalyst 2
n = 10, x = 81, s = 5
See attached photo for the construction of the confidence interval...
