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nekit [7.7K]
3 years ago
8

Find the surface area of the Rectangular Pyramid. Please see the attachment, of course 45 yards ^2 is not the correct answer. Th

anks!

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0

Answer:

Surface area = 39 yards²

Step-by-step explanation:

∵ the surface area of the pyramid = 1/2 pl + base area

  Where p = perimeter of the base , l = slant height

∵ Area of the base = 3 × 3 = 9 yards²

∵ Perimeter of the base = 4 × 3 = 12 yards

∵ Slant height = 5 yards

∴ The surface area = 1/2 × 12 × 5 + 9 = 39 yards²

HACTEHA [7]3 years ago
5 0
<h2>Answer:</h2>

<u>The correct option is </u><u>(B) 39.8 yd²</u>

<h2>Step-by-step explanation:</h2>

A rectangular pyramid consists of four triangular lateral faces and a rectangle base. The sum of the area of the rectangle base and area of the four triangular lateral faces gives the surface area of rectangular pyramid.  We use the following formula

Surface Area = Base Area + Lateral Area

where

Base Area = l × b

and

Lateral Area = 1/2 ls1 + 1/2 bs2 + 1/2 ls1 + 1/2 bs2  = ls1 + bs2

So

Surface Area = Base Area + Lateral Area SA =  lb + ls1 + bs2

Putting the values we get 39.9

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Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

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