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sertanlavr [38]
3 years ago
13

What is the reason that dogs shed

Chemistry
1 answer:
irinina [24]3 years ago
5 0

Answer:

Dogs naturally lose old or damaged hair by shedding. Although shedding. and yes

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WILL MARK BRAINLIEST!!!!
Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Compounds
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})
  2. [DA] Divide [Cancel out units]:                                                                         \displaystyle 5.7015 \ mol \ K_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

7 0
3 years ago
Assume that the biocapacity of Earth does not change and that human population growth continues to increase. How will people's e
Alexandra [31]
A. The Average Ecological footprint will need to decrease . 6-11-18
5 0
3 years ago
Read 2 more answers
How many valence electrons are contained in N, O, and F, respectively? 5, 6, 7 7, 8, 9 3, 2, 1 14, 15, 18
trapecia [35]
Nitogen - 5
Oxygen - 6
Flourine - 7
7 0
3 years ago
using the knowledge of the structures of argon and chlorine. Explain why they are both gases at room temperature ?
aleksley [76]
Because at atmospheric pressure the boiling point is below room temperature, just like Oxygen, Nitrogen etc
3 0
3 years ago
Naturally occurring indium has two isotopes, indium-113(112.9040580 amu) and Indium-115 (114.9038780 amu. The atomic mass of ind
Kruka [31]

Answer:

The answer to your question is: letter c (96%)

Explanation:

Indium -113 (112-9040580 amu) ₁₁₃In

Indium-115 (114.9038780 amu)  ₁₁₅In

Atomic mass of Indium is 114.82 amu ₁₁₄.₈₂In

Formula

Atomic mass = m₁(%₁) +m₂(%₂)  / 100

%₁ = x I established this is an equation

%₂ = 100 - x

Substituting values

114.82 = 112.8040x + 114.9039(100-x) /100    and know we expand and simplify

114.82 = 112.8040x + 11490.39 - 114.9039x  /100

11482 = 112.8040x -114.9039x +11490.39

11482 - 11490.39 = 112.8040x -114.9039x

-8.39 = -2.099x

x = 3.99

Then % of Indium-115 = 100 - 3.99 = 96

5 0
3 years ago
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