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alex41 [277]
3 years ago
14

30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140

Chemistry
1 answer:
kolbaska11 [484]3 years ago
7 0

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT =\frac{Q}{mc}

ΔT =\frac{30000}{23 \times 490} = \frac{30000}{11270} =2.66

Since the difference in temperature is 2.66, then the initial temperature will be

Final temperature - Initial temperature = Change in temperature

140-Initial temperature = 2.66

Initial temperature = 140-2.66 = 137.34 °C

Thus, the initial temperature is 137.34 °C.

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A 0.04328 g sample of gas occupies 10.0-mL at 294.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C
stepan [7]

Answer:

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

<u>Lewis structure is shown in the image below.</u>

<u>The geometry around each carbon atom is linear.</u>

Explanation:

Given that:

Temperature = 294.0 K

V = 10.0 mL = 0.01 L ( 1 mL = 0.001 L )

Pressure = 1.10 atm

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

1.10 atm × 0.01 L = n ×0.0821 L atm/ K mol  × 294.0 K  

⇒n = 0.0004557 mol

Given, mass = 0.04328 g

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0004557\ mole= \frac{0.04328\ g}{Molar\ mass}

<u>Molar mass of the gas sample = 94.9747 g/mol</u>

Given that:-

% of C = 25.305

Molar mass of C = 12.0107 g/mol

% moles of C = 25.305 / 12.0107 = 2.1069

% of Cl = 74.695

Molar mass of Cl = 35.453 g/mol

% moles of Cl = 74.695 / 35.453 = 2.1069

Taking the simplest ratio for C and Cl as:

2.1069 : 2.1069  = 1 : 1

<u>The empirical formula is = CCl</u>

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 35.5 = 47.5 g/mol

Molar mass = 94.9747 g/mol

So,  

Molecular mass = n × Empirical mass

94.9747 = n × 47.5

⇒ n = 2

<u>The molecular formula of the gas sample = C_2Cl_2 </u>

Also,

Valence electrons of carbon = 4

Valence electrons of Chlorine = 7  

The total number of the valence electrons  = 4*2 + 7*2 = 22

The Lewis structure is drawn in such a way that the octet of each atom in the molecule is complete. So,  

The Lewis structure is shown in the image below.

According to the theory, the atoms will form a geometry in such a way that there is minimum repulsion and maximum stability.  The carbon atoms are sp hybridized.

<u>So, it is of linear shape.</u>

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