jack has a bag of fruits if he randomly selects a piece of fruit from the bag it is likely to be an apple what is a possible tha
2 answers:
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Answer:
(12,-6)
Step-by-step explanation:
we have
----> inequality A
---> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
<u><em>Verify each point</em></u>
Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B
case 1) (0,-1)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 2) (0,3)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 3) (-6,-6)
Inequality A
----> is true
Inequality B
----> is not true
therefore
The ordered pair is not a solution of the system
case 4) (12,-6)
Inequality A
----> is true
Inequality B
----> is true
therefore
The ordered pair is a solution of the system (makes true both inequalities)
Answer:
B and C are both correct
Step-by-step explanation:
18/6 = 3
h¹⁰/h¹² = h⁽¹⁰⁻¹²⁾ = h⁻² = 1/h²
the a⁻⁴ term remains unchanged and = 1/a⁴
3a⁻⁴h⁻² =