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ella [17]
3 years ago
11

A 20-foot ladder is leaning against a tree. The bottom of the ladder is 12 feet away from the bottom of the tree. Approximately

how high up the tree does the top of the ladder reach?
A. 2.4 feet

B. 6 feet

C. 9.2 feet

D. 16 feet
Mathematics
2 answers:
Helga [31]3 years ago
6 0

Remark

This is just the Pythagorean Theorem

Formula

a^2 + b^2 = c^2

Givens

a = 12

b = ??

c = 20

Solve

12^2 + b^2 = 20^2         Square 12 and 20

144 + b^2 = 400             Subtract 144 from both sides.

b^2 = 400 - 144          

b^2 = 256                      Take the square root of both sides

sqrt(b^2) = sqrt(256)

b = 16 <<<< Answer

jarptica [38.1K]3 years ago
4 0

Using the Pythagorean Theorem we can solve.


20^2 - 12^2 = X^2

400 - 144 = X^2

256 = X^2

X = √256

X = 16 feet.


The answer is D.

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3 years ago
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How do you check the answer of -6 = x/3
viktelen [127]

Answer:

-6 = x / 3         -Multiply both sides by 3

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8 0
4 years ago
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2

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8 0
3 years ago
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PLEASE HELP!!!!!!!
il63 [147K]
Well to solve for r, what you would need to do is make up an equation based on the expressions that represent the segments of the line in the image.

JK represents the first aspect of the line and is equal to 6r.

Likewise, KL represents the second component of the line and is equal to 3r.

We also know the total value from the first point to the last one, and that is 27.

Now simply add the first 2 expressions that represent the segments of the line and make it equal to the total length of the line, 27 and then solve for r.

6r + 3r = 27
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r = 3.

So now we know that JK is 6 • 3 = 18 and KL is 3 • 3 = 9, thus adding both together will give a value of 27, 18 + 9 = 27.

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