A 20-foot ladder is leaning against a tree. The bottom of the ladder is 12 feet away from the bottom of the tree. Approximately how high up the tree does the top of the ladder reach? A. 2.4 feet
B. 6 feet
C. 9.2 feet
D. 16 feet
2 answers:
Remark
This is just the Pythagorean Theorem
Formula
a^2 + b^2 = c^2
Givens
a = 12
b = ??
c = 20
Solve
12^2 + b^2 = 20^2 Square 12 and 20
144 + b^2 = 400 Subtract 144 from both sides.
b^2 = 400 - 144
b^2 = 256 Take the square root of both sides
sqrt(b^2) = sqrt(256)
b = 16 <<<< Answer
Using the Pythagorean Theorem we can solve.
20^2 - 12^2 = X^2
400 - 144 = X^2
256 = X^2
X = √256
X = 16 feet.
The answer is D.
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A (base) 6
B (Base) 12
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