Answer:
Triangle DEF is a right, scalene triangle. It is not isosceles, obtuse, acute, or equilateral
Step-by-step explanation:
All we know about m and n are that they are not equal to each other and they are positive. This was given in the problem. See image. Once it is graphed you can see on the graph the lengths of DE and EF. Use Pythagorean theorem to calculate DF. see image.
DE is horizontal and EF is vertical, so you can see their slopes or calculate using a formula. Calculate the slope of DF. Slope is y-y on top of a fraction and x-x on the bottom of the fraction.
Lastly, use midpoint formula to find the midpoints. Average the x's and average the y's to find the x- and y-coordinates of the midpoints. See image.
Finally, DEF is a right triangle. The graph as well as the slopes show us that DE and EF form a right angle. So DEF must be a right triangle (and not obtuse nor acute) We were told that m doesNOT equal n, so the triangle cannot have two equal sides, so it cannot be isosceles (2 equal sides) nor equilateral (3 equal sides) It has 3 different lengths of sides; that is called scalene.
Answer:
1.4
Step-by-step explanation:
Answer:
A)Predicted value = 103.5
B)Actual value = 102
C)So, these are not same
Step-by-step explanation:
The researcher used the line
to model the data.
A)When the researcher substituted the value of x = 65 into this equation, what is the resulting y value?
Substitute value x=65 in equation :
y = -0.1 x +110
y=-0.1(65)+110
y=103.5
Predicted value = 103.5
B)Based on the coordinates of the given data points, what is the actual actual vision score when x=65?
Use the given graph
When x = 65
y = 102
So, The actual actual vision score when x=65 is 102
C)When the researcher substituted x = 65 into the line of equation, is the resulting y value the predicted value or the exit value for the vision score of a 65-year-old? Use your results for parts a and b to answer this question.
Predicted value = 103.5
Actual value = 102
So, these are not same
Answer: 112
Step-by-step explanation:
Answer: 2s + 1
Explanation:
1) Given expression: 6s² - 7s- 5 = (3s - 5) ( )
2) The missing factor ( ) is such that when it is multiplied by (3s - 5) the product is 6s² - 7s- 5.
3) Since the first term of the first factor starts with 3s, the first term of the second factor shall be 2s (since they have to yield 6s²). Then, you can write:
6s² - 7s- 5 = (3s - 5) (2s + )
4) The second term of the missing factor is positive because the product (+)(-) = (-) which is the sign of the third term of the polynomial.
5) The second term is such that when multiplied by - 5 is equal to the last term of the polynomial (also - 5), so this second terms is +1.
And you get: 6s² - 7s- 5 = (3s - 5) (2s + 1)
6) You can expand, using distributive property to confirm the result:
(3s - 5) (2s + 1 ) = (3s)(2s) + (3s)(1) - (5)(2s) -(5)(1) = 6s² - 7s- 5, which confirms the result.
