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My name is Ann [436]
3 years ago
10

All of the following are examples of homeostasis within a cell except

Chemistry
2 answers:
weeeeeb [17]3 years ago
6 0
I'd Say (D) Cells Move From One Place To Another...
hoa [83]3 years ago
4 0
D 
is it select all that work or just one?
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Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh
Svet_ta [14]

Answer: The freezing point depression is 1.86^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=K_f\times m

\Delta T_f = Depression in freezing point

K_f = freezing point constant = 1.86^0C/m

m= molality = \frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m

\Delta T_f=1.86mol/kg^0C\times 1m  

\Delta T_f=1.86^0C  

Thus freezing point depression is 1.86^0C

3 0
3 years ago
How does the way in which the solar system formed explain the orbits, sizes, and compositions of the planets?
nexus9112 [7]

Answer:

DUE TO GRAVITATIONAL COLLAPSE SOLAR SYSTEM IS FORMED , ORBITS ARE CURVED TRAJECTORIES AND SIZE AND COMPOSTION OF PLANET ARE VERY UNIQUE AND COMPOSED OF ROCKS AND METALS and evolution of solar system has began 4.5 billion years ago,due to gravitational collapse of a small particle from a giant cloud.

7 0
3 years ago
A galvanic cell consists of a Al3 /Al half-cell and a standard hydrogen electrode. If the Al3 /Al half-cell standard cell functi
11111nata11111 [884]

Answer:

Explanation:

here is your answer:

3 0
3 years ago
Which of the following elements is an example of metal that is not a transition metal?
tamaranim1 [39]
Transition metals are metals found in the middle of the periodic table. The answer is Pb.
4 0
3 years ago
Read 2 more answers
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential
nika2105 [10]

Answer:

3.50*10^-11 mol3 dm-9

Explanation:

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.

Ag2C2O4 -->  2Ag+  +  C2O4 2-

So Ksp = [Ag+]^2 * [C2O42-]

In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.

So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)

= 3.50*10^-11 mol3 dm-9

7 0
3 years ago
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