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Anastaziya [24]
3 years ago
15

How many atoms of oxygen are in 0.100 mol of silicon dioxide?

Chemistry
1 answer:
lys-0071 [83]3 years ago
3 0
1) Silicon dioxide formula: SiO2  ....... 2 is a subscript for the O atom

2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2

3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si

4) Multiply by Avogadro's number: 0.100mol *  6.022*10^23 atoms/mol= 6.02*10^22 atoms

Answer: 6.02*10^22 atoms
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Svetlanka [38]
Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
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