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Viefleur [7K]
3 years ago
12

Which of these numbers is irrational (The demontar on the last fraction is 3 BTW)

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0
Letter a would be the best answer
nataly862011 [7]3 years ago
3 0

An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point. The answer is A. Please mark brainliest

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Would x= 8 be a solution to equation × +10=24?​
ella [17]

Answer:

No, 8+10=18 but, 14+10=24 which means x=14

Step-by-step explanation:

6 0
3 years ago
What is this number in expanded form?
rodikova [14]

Answer:

100,000 + 30,000 + 900 + 80 + 7

(Brainliest please! :D)

5 0
3 years ago
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Which expression is equal to 20.92 ÷ 6.8?
vesna_86 [32]

Answer:

D

Step-by-step explanation:

They both equal 3.08

The decimal is moved one to the right on both so the answer will be the same

4 0
3 years ago
A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio
Klio2033 [76]

Answer:

  • k = 0.032
  • P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

  • k = 0.032
  • P0 = 131.836
4 0
2 years ago
Percy plotted the points (5,6)
Annette [7]

Answer:

1,6 and 6,6

Step-by-step explanation:

since they are on the same y-axis, changing the x-value shouldn't matter.

3 0
3 years ago
Read 2 more answers
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