All categories

3 years ago

Thermal energy is the _____ of the kinetic and potential energies of all particles in an object.

Chemistry

2 answers:

guajiro [1.7K]3 years ago

5 0

Answer:

sum

Explanation:

konstantin123 [22]3 years ago

3 0

Answer:

diffrence

Explanation:

thermal energy is diffence because you need to go back and learn more and be very take notes

You might be interested in

How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?

yan [13]

Answer: There are $1.08 \times 10^{-14}$ moles $N_{2}O_{4}$ present in $6.49 \times 10^9$ particles.

Explanation:

According to the mole concept, 1 mole of a substance contains $6.022 \times 10^{23}$ particles.

Hence, number of moles present in $6.49 \times 10^9$ particles are calculated as follows.

No. of moles = $\frac{6.49 \times 10^9}{6.022 \times 10^{23}}$ mol

= $1.08 \times 10^{-14}$ mol

Thus, there are $1.08 \times 10^{-14}$ moles $N_{2}O_{4}$ present in $6.49 \times 10^9$ particles.

6 0

3 years ago

Read 2 more answers

How many atoms of Ca are present in 80.156 grams of Ca? (4 points) 1.2044 × 1024 2.4088 × 1024 4.8270 × 1025 1.9346 × 1027

Alika [10]

Answer: 1.2044 × 10^24

Explanation:

1 mole of calcium is 40 gram

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms, also 1 mole of calcium is 40gram

So, 1 mole of calcium = 6.02 x 10^23 atoms

Also, 1 mole of calcium is 40gram

40 grams of calcium = 6.02 x 10^23 atoms

80.156 grams of calcium = Z atoms

To get the value of Z, cross multiply:

Z atoms x 40 grams = 6.02 x 10^23 atoms x 80.156 grams

40Z = 482.54 x 10^23

Z = (482.54 x 10^23/40)

Z = 12.06 x 10^23

Put result in standard form

Z = 1.206 x 10^24 atoms

Thus, 1.206 x 10^24 atoms of Ca are present in 80.156 grams of Ca

6 0

4 years ago

Read 2 more answers

Delta H equals 98.8 KJ, and Delta S equals 141.5 J/K. Is this reaction spontaneous or nonspontaneous at high and low pressure

Softa [21]

A is the answer

Like that high and low

8 0

3 years ago

How many atoms are in a 158.69 g sample of nickel?

Alchen [17]

<h3>Answer:</h3>

1.6283 × 10²⁴ atoms Ni

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Use Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

158.69 g Ni

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Ni - 58.69 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 158.69 \ g \ Ni(\frac{1 \ mol \ Ni}{58.69 \ g \ Ni})(\frac{6.022 \cdot 10^{23} \ atoms \ Ni}{1 \ mol \ Ni})$
Multiply/Divide: $\displaystyle 1.62827 \cdot 10^{24} \ atoms \ Ni$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

1.62827 × 10²⁴ atoms Ni ≈ 1.6283 × 10²⁴ atoms Ni

8 0

3 years ago

Can you provide an example for both fission and fusion

dsp73

Fission energy is gained by splitting apart heavy atoms fusion is combining light atoms

7 0

3 years ago