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Evgesh-ka [11]
4 years ago
13

Macon is 50 miles from Atlanta. If the time of the trip increases, what happens to the speed? Question 8 options: A:It stays the

same because the distance stays the same B: It decreases C: It averages out to the same speed. D: It increase
Chemistry
2 answers:
Nitella [24]4 years ago
7 0
The answer is B - it decreases.
pashok25 [27]4 years ago
3 0

<u>Given information:</u>

Distance (d) = 50 miles

<u>To determine:</u>

The effect on speed as time increases

<u>Explanation:</u>

Speed can be defined as the ratio of the distance (d) traveled to the time (t) taken to cover that distance

Speed = distance/time -----(1)

In the given example since the distance is fixed an increase in the time of the trip will increase the denominator in equation(1) thereby decreasing the speed.

Ans (B) It decreases

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When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?
ahrayia [7]
1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2 

<span>k1 = n(Al) / 2 = 4,5 / 2 = 2,25 </span>
<span>k2 = n(HCl) / 6 = 11,5 / 6= 1,92 </span>

<span>k2 < k1 ==> HCl is the limiting reactant </span>

<span>6 mol of HCl ---> 2 mol of H2 </span>
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3 years ago
The goose has a mass of 19.2 lb (pounds) and is flying at 7.10 miles/h (miles per hour). What is the kinetic energy of the goose
nata0808 [166]

Answer:

43.868 J

Explanation:

Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).

According to classical mechanics, kinetic energy = 1/2 m·v²

Where, m= mass in kg and v= velocity in m/s

Given: m = 19.2 lb and v = 7.10 miles/h

Since, 1 lb= 0.453592 kg

∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg

Also, 1 mi = 1609.34 m and 1 h = 3600 sec

∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec

Therefore, <u>kinetic energy of the goose</u> = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J

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3 years ago
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