Answer: 162.8 grams
Explanation:
Magnesium nitrate has a chemical formula of Mg(NO3)2.
Given that:
Number of moles of Mg(NO3)2 = 1.1 moles
Mass in grams of Mg(NO3)2 = ?
For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g
Mg(NO3)2 = 24g + (14g + 16gx3) x 2
= 24g + (14g + 48g) x 2
= 24g + (62g) x 2
= 24g + 124g
= 148g/mol
Now, apply the formula:
Number of moles = Mass in grams / molar mass
1.1 moles = Mass / 148g/mol
Mass = 1.1 moles x 148g/mol
Mass = 162.8 grams
Thus, there are 162.8 grams of magnesium nitrate.
Answer:
In cellular respiration, cells use <u>oxygen</u> to release energy stored in <u>glucose</u>.
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When Al(OH)3 and H2SO4 are allowed to react, the products formed are aluminum sulfate (Al2(SO4)3<span> ) and water (H2O). The balanced equation should be written as follows:
</span><span>3H2SO4 + 2Al(OH)3 = Al2(SO4)3 + 6H2O
This reaction is called a neutralization reaction. Hope this answers the question. Have a nice day.</span>
