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oee [108]
3 years ago
9

Can someone help me please? the last point of the first graph ends on 6 ​

Mathematics
1 answer:
just olya [345]3 years ago
5 0

Answer:

a) Yes

b) for reference, draw the line y = x, and reflect it over that, this reflection will be your inverse. Or switch the x and y values of each point of the function.

Here is a photo of the original function in black, it's inverse in red, and the line of reflection y = x in blue:

c) No, because it fails the vertical line test, when you draw a vertical line across the inverse function, it hits it more than once.

d) Domain of the original function: -6 ≤ x ≤ 6 ; x(the domain) is greater than or equal to -6 and less than or equal to 6.

e) Domain of inverse function: 0 ≤ x ≤ 4 ; x(the domain) is greater than or equal to 0 and less than or equal to 4.

f) Range of the original function: 0 ≤ y ≤ 4 ; y(the range) is greater than or equal to 0 and less than or equal to 4.

e2) Range of the inverse function: -6 ≤ y ≤ 6 ; y(the range) is greater than or equal to -6 and less than or equal to 6.

f2) x-intercept of original function: -6

g) y-intercept of the inverse function: -6

h) x-intercept of the inverse function: 4

i) y-intercept of the original function: 4

j) (2,2) or any point where the x, and y are the same within the function, or the point where the function intersects y = x.

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The label on a package of bolts says each bolt has a diameter of 0.35 inch. To be in the package, the percent error of the diame
qaws [65]

Answer: No

Step-by-step explanation:-

Labeled diameter on the bolt = 0.35 inch

The observed diameter of the bolt= 0.33 inch

{\text {Percentage Error}}=|\frac{\text {labeled value}-{Observed value}}{\text {Observed value}}|\times 100\%

{\text{Percentage Error}=|\frac{0.35-0.33}{0.33}|\times 100\%=6.06\%

For the bolt to be in the package, the percent error must be less than 5%. As the percent error is 6.06% which is greater than 5%, the bolt cannot be in the package.



7 0
3 years ago
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Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
7 0
3 years ago
Helpppppp please please
GenaCL600 [577]
3/10=4/x
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3 years ago
Ms Lemon has $150 to spend on the parking and admission to the zoo.The parking will cost $18, and the admission tickets will cos
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Answer:

Let y be the no. of people she can bring

18 + 16.5y <= 150

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