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Lapatulllka [165]
3 years ago
12

Katie has a cat named

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

1/2 a cup or 0.5 cups per serving

Step-by-step explanation:

If you were to divide 7 by 14 you would get 0.5. The reason as to why you would divide 7 by 14 is because if she eats twice a day that would be 7 more times then if she were to be fed once a day. So if you  were to feed her twice a day that would be 14 times a week.

Don't think this helped at all but I tried my hardest, sorry if you get your problem wrong. Hope you have a good day :D

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Plz plz help test due soon
Dvinal [7]

Answer:

22

Step-by-step explanation:

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3 years ago
Josiah went to the local barber to get his haircut.it cost 18 for the haircut.josiah tipped the barber 15%.what was the total co
dalvyx [7]
$20.70
Eighteen dollars
Fifteen percent of eighteen is 2.7 
(.15 X 18)+18
4 0
3 years ago
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Evaluate -8y+x5 when x =2 and y= -3
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A center for medical services reported that there were 295,000 appeals for hospitalization and other services. For this group, 4
pshichka [43]

Answer:

a) 0.0025 = 0.25% probability that none of the appeals will be successful.

b) 0.0207 = 2.07% probability that exactly one of the appeals will be successful.

c) 0.9768 = 97.68% probability that at least two of the appeals will be successful

Step-by-step explanation:

For each appeal, there are only two possible outcomes. Either it is succesful, or it is not. The probability of an appeal being succesful is independent of other appeals, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

45% of first-round appeals were successful.

This means that p = 0.45

Suppose 10 first-round appeals have just been received by a Medicare appeals office.

This means that n = 10

(a) Compute the probability that none of the appeals will be successful.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.45)^{0}.(0.55)^{10} = 0.0025

0.0025 = 0.25% probability that none of the appeals will be successful.

(b) Compute the probability that exactly one of the appeals will be successful.

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.45)^{1}.(0.55)^{9} = 0.0207

0.0207 = 2.07% probability that exactly one of the appeals will be successful.

(c) What is the probability that at least two of the appeals will be successful

This is P(X \geq 2)

Either less than two appeals are succesful, or at least two are. The sum of the probabilities of these events is decimal 1. So

P(X < 2) + P(X \geq 2) = 1

P(X < 2) = P(X = 0) + P(X = 1) = 0.0025 + 0.0207 = 0.0232

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0232 = 0.9768

0.9768 = 97.68% probability that at least two of the appeals will be successful

6 0
3 years ago
Is this correct please correct me if i’m wrong.
Sever21 [200]

Answer: This is correct already.

Step-by-step explanation:

7 0
3 years ago
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