What is the gravitational force between 90kg man and his 35 kg dog when they are 3m apart ?

a 62.0 kg curler runs into a stationary 78.1 kg curler and they hold on to each other. Together they move away at 1.29 m/s, west

Lady_Fox [76]

Momentum P is given by:
$P = mv$

Given: m₁ = 62 kg, m₂ = 78.1 kg, v₁ = ?, v₂ = 0 m/s, v₁₊₂ = 1.29 m/s

before:
$P = m_1 v_1 * m_2 v_2 = m_1 v_1$

after:
$P = (m_1 + m_2)v_{1+2}$

Since momentum is conserved, the momentum before the collision must be equal to the momentum after the collision.

$P = m_1 v_1 = (m_1 + m_2)v_{1+2} \\ v_1 = \frac{(m_1 + m_2)v_{1+2}}{m_1}$

Solve for v₁.

7 0

3 years ago

If Team 4 wants to increase the horizontal distance that the skittles are projected through the air but keep the height as close

photoshop1234 [79]

Answer:

The speed of the catapult arm needs to be increased.

Explanation:

If the height needs to stay the same, they can not change the length of the catapult arm because this is the variable that determines the height of the thrown object. To change the horizontal distance the object travels, in other words the object's speed, the rope or counterweigth that pulls the catapult arm can be changed to increase the speed that the object is thrown.

I hope this answer helps.

3 0

3 years ago

1) When making a digital animation of a person running on a sidewalk in a scene, which parameter would be an initial condition?

lbvjy [14]

Answer:

The position of the person's feet. a running shoe company studying how different surfaces affect the life of a shoe tread

Explanation:

100%

4 0

3 years ago

Two in-phase loudspeakers are 3.0 m apart. they emit sound with a frequency of 490 hz. a microphone is placed half-way between t

stira [4]

Answer:

0.35 m

Explanation:

Constructive interference occurs when the difference in the distance between the two speakers is

0, λ, 2λ,...

Here λ = v/f = 343/490 = 0.7m

The first point of interference is the initial point which would mean the distance is the trivial solution of 0 .

A microphone is placed half-way between the speakers and then moved along the line joining the two speakers until the first point of constructive interference is found.

Let x be the distance from the midpoint to the next interference.

This occurs when 1.5 + x -(1.5 - x) = 0.7

so 2x = 0.7 which means x = 0.7/2 = 0.35m

3 0

4 years ago

Soap bubbles can display impressive colors, which are the result of the enhanced reflection of light of particular wavelengths f

Bogdan [553]

Answer:

the minimum wall thickness that will enhance the reflection of light is 146.9 nm

Explanation:

Given the data in the question;

At the first interface, a phase shift occurs as the incident light is in air that has less refractive index compare to the thin film of soap bubble.

At the second interface, no shift occurs,

condition for constructive interference;

t = ( m + 1/2) × λ/2n

where m = 0, 1, 2, 3 . . . . . .

now, the condition for the constructive interference;

t = mλ/2n

where t is the thickness of the soap bubble, λ is the wavelength of light and n is the refractive index of soap bubble.

so the minimum thickness of the film which will enhance reflection of light will be;

t $_{min$ = ( m + 1/2) × λ/2n

we substitute

t $_{min$ = ( 0 + 1/2) × 711 /2(1.21)

t $_{min$ = 0.5 × 711/2.42

t $_{min$ = 0.5 × 293.80165

t $_{min$ = 146.9 nm

Therefore, the minimum wall thickness that will enhance the reflection of light is 146.9 nm

8 0

3 years ago