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GREYUIT [131]
3 years ago
7

Ipaliwanag ang paggalang

Physics
1 answer:
cestrela7 [59]3 years ago
5 0

paraan ito ng pagrerespeto

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A thin metallic spherical shell of radius 0.357 m has a total charge of 5.03 times 10^-6 C placed on it. At the center of the sh
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Answer:

The electric field is 5.623\times10^{4}\ N/C

Explanation:

Given that,

Radius = 0.357 m

Charge Q=5.03\times10^{-6}\ C

Point charge q=4.15\times10^{-6}\ C

Distance = 0.815 m

We need to calculate the total electric field

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q}{r^2}

Where, q = point charge

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times4.15\times10^{-6}}{(0.815)^2}

E=5.623\times10^{4}\ N/C

Hence, The electric field is 5.623\times10^{4}\ N/C

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