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GREYUIT [131]
3 years ago
7

Ipaliwanag ang paggalang

Physics
1 answer:
cestrela7 [59]3 years ago
5 0

paraan ito ng pagrerespeto

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Who was the first man to walk on the moon?
Andrej [43]
The first person is Neil Armstrong
8 0
4 years ago
Help!
muminat

Power P is the rate at which energy is generated or consumed and hence is measured in units that represent energy E per unit time t. This is:

P = E/t

Solving for t:

t = E/P

t = 6007 J / 500 W

t = 12.014 s

<h2>t ≅ 12 s</h2>

7 0
3 years ago
What is the nucleon A number of carbon-14?Express your answer as aninteger.
Deffense [45]

Answer:

14

Explanation:

The total no of protons and neutrons in an atomic nucleus is called mass number, nucleon number or atomic mass number. It is denoted by A.

In this problem, we need to find the nucleon number of carbon-14 i.e. mass number of carbon -14. 14 with carbon shows its mass number.

Hence, the nucleon no of carbon-14 is 14.

7 0
3 years ago
For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

8 0
4 years ago
What is the density of an object with a volume of 20 cm3 and a mass of 40g?
melisa1 [442]
Density = mass/volume
Density = 40g/20cm^3
Density = 2g/cm^3
3 0
3 years ago
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