
To solve this equation , we need to write it in quadratic form

To get the equation in quadratic form we replace x^2 with u

can be written as
, Replace u for x^2
So equation becomes

Now we factor the left hand side
-16 and -1 are the two factors whose product is +16 and sum is -17
(u-16) (u-1) = 0
u -16 = 0 so u=16
u-1 =0 so u=1
WE assume u = x^2, Now we replace u with x^2
Now take square root on both sides , x= +4 and x=-4
Now take square root on both sides , x= +1 and x=-1
So zeros of the function are -4, -1, 1, 4
<h3>
Answer: 9 meters</h3>
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Work Shown:
- side a = 8
- side b = 5
- angle C = 88 degrees
Applying the law of cosines
c^2 = a^2 + b^2 - 2*a*b*cos(C)
c^2 = 8^2 + 5^2 - 2*8*5*cos(88)
c^2 = 64 + 25 - 80*cos(88)
c^2 = 86.2080403
c = sqrt(86.2080403)
c = 9.2848285
c = 9
Technically he needs 10 meters of rope because of the extra 0.28 portion, but I'll stick with 9 meters since your teacher said to round to the nearest whole number.
Q1
Answer:

Step-by-step explanation:

explanation for second step:
you divide each side by 3 to get rid of the '3' in '3x'
Step-by-step explanation:
The equation of a parabola with focus at (h, k) and the directrix y = p is given by the following formula:
(y - k)^2 = 4 * f * (x - h)
In this case, the focus is at the origin (0, 0) and the directrix is the line y = -1.3, so the equation representing the cross section of the reflector is:
y^2 = 4 * f * x
= 4 * (-1.3) * x
= -5.2x
The depth of the reflector is the distance from the vertex to the directrix. In this case, the vertex is at the origin, so the depth is simply the distance from the origin to the line y = -1.3. Since the directrix is a horizontal line, this distance is simply the absolute value of the y-coordinate of the line, which is 1.3 inches. Therefore, the depth of the reflector is approximately 1.3 inches.
Answer:![\frac{20+5\sqrt[]{3} }{13}](https://tex.z-dn.net/?f=%5Cfrac%7B20%2B5%5Csqrt%5B%5D%7B3%7D%20%7D%7B13%7D)
Step-by-step explanation: