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Colt1911 [192]
3 years ago
11

What is 1.234 + 8.89?

Mathematics
2 answers:
Helen [10]3 years ago
4 0

Hi



Answer: 10.124


Step-by-step explanation:


  1.234

+ 8.890

_______




  1.234

+8.890

_______

           4



     1

  1.234

+ 8.890

______

        2 4


  1 1

  1.234

+ 8.890

______

      1 2 4


1 1 1

  1.234

+ 8.890

_______

 0 . 1 2 4


1 1 1

  1.234

+ 8.890

______

10. 1 2 4


Hope this helps you!!



goldenfox [79]3 years ago
3 0

Answer:


Step-by-step explanation:

The answer is 10.124

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6. How much more is (6.48 x 10^5) than (3.2 x 10^2​
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Answer:

647680

Step-by-step explanation:

3 0
3 years ago
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Mrs. Allan's car uses 8 gallons of gas for a 224-mile trip. Mrs. Owen's car uses 6 gallons of gas for a 210-mile trip. How many
Feliz [49]

Answer:

Mrs. Allan's Car will use <u>20 gallons</u> of gas for 560 miles trip.

Mrs. Owen's Car will use <u>16 gallons</u> of gas for 560 miles trip.

Step-by-step explanation:

Given:

Number of Miles for Mrs Allan car = 224 miles

Number of gallons of gas required = 8

We need to find the number of gallons of gas required for 560 miles for Mrs. Allan's car.

First we will find, in 1 gallons how many miles does Mrs Allan's Car drives.

For 8 gallons = 224 miles

So for 1 gallons = Number of miles in 1 gallon of gas

By using Unitary method we get;

Number of miles in 1 gallon of gas = \frac{224}{8}= 28\ miles

Now we know that;

for 28 miles = 1 gallon of gas is required.

So for 560 miles = Number of gallon of gas required in 560 miles.

Again by using Unitary method we get;

Number of gallon of gas required in 560 miles = \frac{560}{28}= 20\ gallons

Hence Mrs. Allan's Car will use <u>20 gallons</u> of gas for 560 miles trip.

Also Given:

Number of Miles for Mrs Owen's car = 210 miles

Number of gallons of gas required = 6

We need to find the number of gallons of gas required for 560 miles for Mrs. Owen's car.

First we will find, in 1 gallons how many miles does Mrs Owen's Car drives.

For 6 gallons = 210 miles

So for 1 gallons = Number of miles in 1 gallon of gas

By using Unitary method we get;

Number of miles in 1 gallon of gas = \frac{210}{6}= 35\ miles

Now we know that;

for 35 miles = 1 gallon of gas is required.

So for 560 miles = Number of gallon of gas required in 560 miles.

Again by using Unitary method we get;

Number of gallon of gas required in 560 miles = \frac{560}{35}= 16\ gallons

Hence Mrs. Owen's Car will use <u>16 gallons</u> of gas for 560 miles trip.

8 0
3 years ago
“Bishon needs to sell at least 0.3 of his Collin sports card to make room for new cards.is 3/20 of his collection enough? Explai
Darya [45]

Answer:

I dont know But maybe the answer is No

Step-by-step explanation:

0.3 is 30% and if 1/10 is 10% then 2/20 must be 10% because 5% is 1/20

so maybe 3/20 is only 15%

I hope this helps :)

Sorry if it dosent i suck at explaining things ; - ;

3 0
3 years ago
A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of
hram777 [196]

\sf\huge\underline{\star Solution:-}

\rightarrow <u>Ratio of two angles are 6:13.</u>

So, let the one angle be \sf{6x} and another be \sf{13x.}

As we know that,

Sum of all interior angles of a quadrilateral = \sf\pink{360°.}

So let's sum up the given angles,

\rightarrow \sf{222°+81°+6x+13x \:=\:  360°}

\rightarrow \sf{303+19x \:=\:  360°}

\rightarrow \sf{19x \:=\:  360-303}

\rightarrow \sf{19x \:=\:  57}

\rightarrow \sf{x \:=\:  \frac{19}{57}}

\rightarrow \sf{x \:=\:  3}

Hence, \sf{x \:=\:  3}

So, First angle \sf{= \:6x\: = \:6×3 \:=} \sf\purple{18°.}

Second angle \sf{= \:13x\: = \:13×3 \:=} \sf\purple{39°.}

_________________________________

Hope it helps you:)

3 0
2 years ago
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Step-by-step explanation:

The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.

Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.

What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.

Doing this 125 times, we obtain the number of trials we desire.

For each trial, we get for each child, C:

C1: X + (X or Y)

C2: X + (X or Y)

C3: X + (X or Y)

C4: X + (X or Y)

C5: X + (X or Y)

Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.

6 0
2 years ago
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