Hello,
We suppose x≠+/-π/2.
2cos x - √2=0
==>cos x=√2/2
==>x= π/4 or x=3π/4 (modulo 2π)
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
The answer is -5 1/3
Step-by-step explanation:
Answer:
6.08333333 hours
Step-by-step explanation:
((42 hours) + (35 minutes)) / 7 = 6.08333333 hours
hope this helps LOL :)
Answer:
The required probability is 0.04411
Step-by-step explanation:
The number of female grey mice = 5.
The number of males grey mice = 4.
The number of female white mice = 2.
The number of male white mice = 6.
The number of mice = 17.
The probability of first mice be male grey = 
The probability of second mice be male grey = 
The probability of two mice be male grey =
= 0.04411