First, we obtain the gradient (slope) of the first parallel line

Recall that since both lines are parallel, we have that,

Thus

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)
Using
Answer:
C
Step-by-step explanation:
A = 1/2bh
40 = 1/2 x^2
x^2 = 80
x = 8.9
The figure below shows a parallelogram PQRS:
A parallelogram PQRS is shown with the diagonal SQ.
The flowchart shown below shows the sequence of steps to prove the theorem: Opposite angles of a parallelogram are equal:
Which is the missing statement?
Answer - Triangle PQS is congruent to triangle RSQ