Question

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′

Answer 1

Answer:

The distance from B to B' is 5 units

Step-by-step explanation:

we know that

A translation is a rigid transformation, that means, the size and the shape of the pre-image is the same that the size and the shape of the image after the translation

so

The distance AA' will be equal to the distance BB'

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(1,5) and A'(-2,1)

substitute

$d=\sqrt{(1-5)^{2}+(-2-1)^{2}}$

$d=\sqrt{(-4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$d=5\ units$

therefore

The distance from B to B' is 5 units