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nevsk [136]
3 years ago
11

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is

the distance from B to B′
Mathematics
1 answer:
never [62]3 years ago
3 0

Answer:

The distance from B to B' is 5 units

Step-by-step explanation:

we know that

A translation is a rigid transformation, that means, the size and the shape of the pre-image is the same that the size and the shape of the image after the translation

so

The distance AA' will be equal to the distance BB'

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(1,5) and A'(-2,1)

substitute

d=\sqrt{(1-5)^{2}+(-2-1)^{2}}

d=\sqrt{(-4)^{2}+(-3)^{2}}

d=\sqrt{25}

d=5\ units

therefore

The distance from B to B' is 5 units

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laiz [17]

Answer:

x=(3,1/4)

Step-by-step explanation:

Be sure to use the formula...

-b + or - sqrt{b^{2} - 4ac } / 2a

- First, move all variables to one side (left) of the equation. You want one side to be equivalent to zero.

-Next, you need to find a, b, and c. This should be...

a=4

b=-13

c=3

- Knowing this, fill in these variable to go along with the formula. I cannot do this for you, as you should try it on your own. But, you should end up with the solution x= (3,1/4).

- Hope this helps! If you need a further explanation or help on any more problems please let me know, as I would be glad to help anytime.

5 0
3 years ago
20 POINTS QUESTION IN PICTURE
Serga [27]
Domain includes all the x-values in the function. Range includes all the y-values in the function.

The first table has x-values of -1, 3, and 6, and y-values of 4, 5, and 6. This means that the domain and range would be given by the following sets:
Domain: {-1, 3, 6}
Range: {4, 5, 6}

The second set of points has x-values of -4, -4, -3, and 1, and y-values of 1, 1, 3, and 4. Duplicate points are not listed within the domain and range, so the domain and range would be given by the following sets:
Domain: {-4, -3, 1}
Range: {1, 3, 4}
7 0
3 years ago
Read 2 more answers
If the freshman class of 63 students has 11 more boys than girls, determine how many of each are in the class.g 1
torisob [31]
B + G = 63
B = G + 11

G + 11 + G = 63
2G + 11 = 63
2G = 63 - 11
2G = 52
G = 52/2
G = 26 <=== 26 girls

B = G + 11
B = 26 + 11
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4 0
3 years ago
Can someone please answer this and explain it?
professor190 [17]

Answer:

Velocity = displacement / time

Distance = 3t^2 +2t +6 to find distance you need to plug in time = 2 sec

Distance = 3(2)^2 +2(2) +6

Distance = 3(4) +4 + 6

Distance = 12 + 4 +6

Distance = 22 meters

In this problem the displacement is the distance.

so

Velocity = 22 meters / 2 second

Velocity = 11 meters/second

Does this help?

Step-by-step explanation:

4 0
3 years ago
Can you give a reason why a calculator shows 2/3 equal to 0.666666667
frosja888 [35]
This is because 2÷3 = 0 . Six repeating but the Calculator rounds the last 6 to 7 because I can't fit all the repeating sixes in one calculator
6 0
3 years ago
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