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Sunny_sXe [5.5K]
3 years ago
6

Agustin has 1/4 as many cards as mateo.mateo has 1/2 as amaro.who has the most cards?

Mathematics
1 answer:
Ket [755]3 years ago
5 0

Answer:

amaro

Step-by-step explanation:

amaro has double the amount of cards as mateo and mateo has more than agustin, therefore amaro has the most cards.

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Pleaseee help meee will give brainliest or whateva
____ [38]

Answer:

The value of x = 12.

Step-by-step explanation:

We know that two angles are termed as supplementary when the sum of the measure of their angles is 180°.

We also know that a straight line angle measures 180°.

It is clear that the angles 72° and 9x° line on a straight line. Thus, the sum of the measure of their angles is 180°.

Therefore,

9x° + 72° = 180°

9x° = 180° - 72°

9x° = 108

divide both sides by 9

9x/9 = 108/9

x = 12

Therefore, the value of x = 12.

5 0
3 years ago
The positive integer k has exactly two positive prime factors, 3 and 7. if k has a total of 6 positive factors, including 1 and
Sav [38]
I think there are two solutions, 63 or 147:

63 = 3² x 7, factors  1 | 3 | 7 | 9 | 21 | 63<span>
147 = 3 x 7</span>², factors 1 | 3 | 7 | 21 | 49 | 147
5 0
3 years ago
What is the median of the following number: 40, 49, 62, 56, 68, 39, 50, 61, 54, 44
Karo-lina-s [1.5K]

Answer:

52

Step-by-step explanation:

39, 40, 44, 49, 50, 54, 56, 61, 62, 68

39, 40, 44, 49, <u>50, 54,</u> 56, 61, 62, 68

\frac{50 + 54}{2} = \frac{104}{2} = 52

6 0
3 years ago
Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins
bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = \frac{360 - 80y}{60}

Substituing x into the second equation:

160(\frac{360 - 80y}{60}) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = \frac{360 - 80y}{60}

x = \frac{360 - 80.3}{60}

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0
3 years ago
What type of dilation occurs with a scale factor of 1/4?
Natasha2012 [34]

Answer:

Congruent

Step-by-step explanation:

3 0
3 years ago
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