Soooo Hard Please someone help me
1 answer:
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Answer: 352
Step-by-step explanation:
To find the Lateral area of a square pyramid , we will follow the three steps below:
1. Find the perimeter of the base
2. Multiply the perimeter by the slant height
3. Divide the result above by 2
That is :
The lateral surface area of a regular pyramid is lateral area = perimeter of base x slant height of pyramid) ÷ 2.
Applying the formula above:
1. The base is a square , therefore the perimeter of a square is 4L , That is
Perimeter = 4(8)
Perimeter = 32m
2. Perimeter x slant height , that is
32 x 22 = 704m
3. Dividing the result by 2 , we have :
704/2 = 352
Therefore , the Lateral area of the pyramid is 352
Answer:
The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.
Step-by-step explanation:
Using Pythagoras' Theorem, a²+b² = c² :
Let a be x cm,
Let b be x+7 cm,
Let c be 2x+1 cm
x² + (x+7)² = (2x+1)²
x² + x² + 14x + 49 = 4x² + 4x + 1
2x² + 14x + 49 = 4x² + 4x + 1
Then, move all the variables to one side and solve it to find the value of x :
4x² + 4x + 1 - 2x² - 14x - 49 = 0
2x² - 10x - 48 = 0
2(x² - 5x - 24) = 0
x² - 5x - 24 = 0
(x-8)(x+3) = 0
x - 8 = 0
x = 8 cm
x + 3 = 0
x = -3 cm (rejected)
Substitute the x value into the length of a,b and c :
a = x
= 8 cm
b = x + 7
= 8 + 7
= 15 cm
c = 2x + 1
= 2(8) + 1
= 16 + 1
= 17 cm
