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elixir [45]
3 years ago
11

Do the side lengths of 12, 15, and 9 form a triangle? *

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0

Answer:

Yes,they do.

Step-by-step explanation:

A triangle base with sides 9,12, and 15 is a right triangle.

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Triangles F H G and K J G share common point G. The lengths of sides H G and G J are congruent. Angles F H G and K J G are right
jenyasd209 [6]

Answer:

not enough information given

Step-by-step explanation:

as the rules say, we need at least 3 pieces of information :

2 angles and a side, or 3 angles (or there are other options like 2 sides and one angle or 3 sides).

but here we get 1 side and 1 angle. the shared point does not give us anything in that regard.

so, not enough information.

7 0
2 years ago
If the APY of savings account is 4.7% and if the principal in the savings account is $4500 for an entire year what will the bala
Ira Lisetskai [31]
Total = 4,500 * (1.047)^1
<span><span><span>Total = 4,711.5</span></span></span>0


6 0
3 years ago
Read 2 more answers
Each data point represents a single white dwarf supernova that has been observed. the data points that appear farthest to the le
MakcuM [25]
A type Ia supernova is a type of supernova that occurs in binary systems (two stars orbiting one another) in which one of the stars is a white dwarf. The other star can be anything from a giant star to an even smaller white dwarf<span>.

I hope my answer has come to your help. God bless and have a nice day ahead!
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6 0
3 years ago
use a protractor to draw an angle of 55 degree that opens from the left.then draw an angle of 125 degree that opens from the rig
lisov135 [29]
You should first draw a strait line across your paper. Draw the 55 degree angle with your protractor. Then draw the 125 degree angle it should stop at where the line of the 55 degree angle you just drew. These two angles add up to 180 degrees. 125+55 = 180. These are known as supplementary angles.
5 0
3 years ago
The remainder when aa is divided by 77 is 22 and the remainder when bb is divided by 77 is 55. (so a mod 7=2a mod 7=2, b mod 7=5
olasank [31]
a\equiv2\pmod7
b\equiv5\pmod7

a+a\equiv2+2\equiv4\pmod7

a+b\equiv2+5\equiv7\equiv0\pmod7

3a\equiv6\pmod7

2b\equiv10\equiv3\pmod7
7 0
3 years ago
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