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lorasvet [3.4K]
2 years ago
12

Two objects are dropped from a bridge, an interval of 1.00 s apart. What is their separation 1.00 s after the second object is r

eleased
Physics
1 answer:
katen-ka-za [31]2 years ago
4 0

Answer:

<em>171.5m</em>

Explanation:

The velocity of sound in water = 343m/s

Time taken = 1.00secs

using the formula to calculate the distance

2x = vt

x is the distance

v is the speed of sound

t is the time

x = vt/2

x = 343(1)/2

x = 171.5m

<em>hence their separation 1.00 s after the second object is released is 171.5m</em>

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