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valentinak56 [21]
3 years ago
8

you have two solid substances that look the same. what measurements would you take and what tests would you perform to determine

whether they actually are the same
Chemistry
1 answer:
andreev551 [17]3 years ago
8 0


The easiest way to go about this would be to check out their physical properties. Physical properties are those attributes of a substance or material that can be observed or measured without altering or changing the composition of that material.

So we can check out the following physical properties:

1. Color. Check if there is any difference in color.

2. Weight. If possible, take similar sized pieces of the two and note any difference in weight .

3. Texture. Are they smooth or rough to the touch?

4. Smell or odor. Check out any unique smell.

5. Solubility. Dissolve a bit of each in water and see how soluble each is.

6. Melting point. Carefully heat a piece of it and see if they will melt, and if so at what temperature.

7. Pliability. Can any of them bend, are they flexible?

8. Magnetism. Can the be attracted by a magnet?

9. Bouyancy . Can they float on water?

10. Electrical conductivity. using a battery and small torch bulb, find out if they can conduct an electric current.

These 10 physical tests can help differentiate between the two materials. There are  still many more that can  be safely carried out.

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does the nitro group on the pyridine ring make the ring more electron rich or more electron deficient
Arte-miy333 [17]

Answer:

more electron deficient

Explanation:

The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.

This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

3 0
3 years ago
Iron is obtained commercially by the reaction of hematite (Fe2O3) with carbon monoxide. How many grams of iron are produced if 1
kherson [118]
 <span>CO is the limiting reactant 
( 25.0 x 3 = 75 moles of CO are required) 

Moles Fe = 30.0 x 2 / 3 = 20.0 
mass Fe = 20.0 x 55.847 g/mol=1117 g </span><span>

I'm just saying</span>
5 0
3 years ago
A student is studying a sample of carbon dioxide gas inside a small syringe. At constant temperature the syringe has a volume of
Soloha48 [4]

The new pressure inside the syringe will be 1.25 atm

<h3>Gas law</h3>

At constant temperatures, the volume of a gas is inversely proportional to its pressure.

Thus:   P1V1 = P2V2

In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL

P2 = P1V1/V2

                         = 3 x 89.6/215

                              = 1.25 atm

More on gas laws can be found here: brainly.com/question/1190311

4 0
2 years ago
Using the Bohr model, determine the energy in joules of the photon produced when an electron in a Li2+ ion moves from the orbit
djverab [1.8K]

Answer:

1.64x10⁻¹⁸ J

Explanation:

By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.

When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:

E = hc/λ

Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.

The wavelength can be calculated by:

1/λ = R*(1/nf² - 1/ni²)

Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:

1/λ = 1.097x10⁷ *(1/1² - 1/2²)

1/λ = 8.227x10⁶

λ = 1.215x10⁻⁷ m

So, the energy is:

E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)

E = 1.64x10⁻¹⁸ J

3 0
3 years ago
What is the boiling point of a solution containing 203 g of ethylene glycol (C2H6O2) and 1035 g of water? (Kb for water is 0.52
Andru [333]

Answer:

101,37°C

Explanation:

Boiling point elevation is one of the colligative properties of matter. The formula is:

ΔT = kb×m <em>(1)</em>

Where:

ΔT is change in boiling point: (X-100°C) -X is the boiling point of the solution-

kb is ebulloscopic constant (0,52°C/m)

And m is molality of solution (mol of ethylene glycol / kg of solution). Moles of ethylene glycol (MW: 62,07g/mol):

203g × (1mol /62,07g) = <em>3,27moles of ethlyene glycol</em>

<em />

Molality is: 3,27moles of ethlyene glycol / (1,035kg + 0,203kg) = 2,64m

Replacing these values in (1):

X - 100°C = 0,52°C/m×2,64m

X - 100°C = 1,37°C

<em>X = 101,37°C</em>

<em></em>

I hope it helps!

7 0
3 years ago
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