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erastovalidia [21]
2 years ago
9

What is the oxidation state of N in NaNO3? O A. +6 B. +5 O C. -1 o D. O

Chemistry
1 answer:
Aleks [24]2 years ago
3 0
The oxidation state of N is

B.+5
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<u>Answer:</u> The value of K_{eq} is 4.84\times 10^{-5}

<u>Explanation:</u>

We are given:

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<u>At eqllm:</u>    0.0280-4x   0.0120-3x   2x       6x

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The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[H_2O]^6\times [N_2]^2}{[NH_3]^4\times [O_2]^3}

Putting values in above expression, we get:

K_{eq}=\frac{(0.009)^6\times (0.003)^2}{(0.022)^4\times (0.0075)^3}\\\\K_{eq}=4.84\times 10^{-5}

Hence, the value of K_{eq} is 4.84\times 10^{-5}

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